Java正则表达式匹配列表中的一个或多个字符

Question

I have some strings:

• total 19xx.100
• total 19x..100
• total 19..100
• total 19x .100

And I want to separate 19 with ("x" or "." one or more times) and 100. I tried to use regex:

 (x|\.)+

to group but it can not match all case above. Which regex can match all case above?

Answer 1

You can use regex:

public static Matcher split(String text) {
    Pattern pattern = Pattern.compile("(\\d+)(x*)(\\s*)(\\.*)(\\d+)");
    Matcher matcher = pattern.matcher(text);
    matcher.find();

    return matcher;
}

This regex works for test data:

19xx.100
19x.100
19..100
19x .100

After then matcher.group(1) will return 19 and matcher.group(5) will return 100

Answer 2

For your example, you could capture what is before 100 and 100 in 2 capturing groups:

(\\d+[x. ]+)(\\d+)

Explanation

• Capturing group (group 1) (
• Match one or more digits \\d+
• Match one or more times x , . or whitespace [x. ]+ [x. ]+ using a character class
• Close capturing group )
• Capture in a group (group 2) one or more digits (\\d+)

Answer 3

You may use

(\d+)(\s*[x.][x.\s]*)(\d+)

See the regex demo

Details

• (\\d+) - Group 1: one or more digits
• (\\s*[x.][x.\\s]*) - Group 2:
  • \\s* - 0+ whitespaces
  • [x.] - an x or .
  • [x.\\s]* - 0+ chars that are either x , . or whitespace chars
• (\\d+) - Group 3: one or more digits