如何随机获取文件的第n个文件段？

Question

I have a file, and I want to divide it in chunks of max_size = 1mb .

Now for example if I have a file - file.zip of size 10 MB , my file segments are file.zip.1, file.zip.2 . . . . file.zip.n

So given a n , can I directly retrieve file.zip.n ?

Or in other words I dont want to loop through the entire file to get the nth file segment. Is there any way by which I can get the iterator to the position in which the nth segment starts?

Answer 1

I have solved it!

Had to create an object RandomAccessFile class, and use the seek() method to skip required number of bytes.