如何在bash脚本中将cat输出路径获取为变量

Question

I'm using cat to create a new file via a shell script. It looks something like:

./script.sh > output.txt

How can I access output.txt as a variable in my script. I've tried $1 but that doesn't work.

The script looks something like:

#!/bin/sh

cat  << EOF
echo "stuff"
EOF

---

Since there doesn't apear to be an os-agnostic way to do this, is there a way I pass the output into the script as an argument and then save the cat results to a file inside the script?

So the command would look like: ./script.sh output.txt and I can access the output as $1. Is something like this possible?

Answer 1

The Literal Question: Determining Where Your Stdout Was Redirected To

When a user runs:

./yourscript >outfile

...they're telling their shell to open outfile for write, and connect it to the stdout of your script, before starting your script. Consequently, all the operations on the filename are already finished when your script is started, so the name isn't passed to the script directly.

On Linux (only), you can access the location to which your stdout was redirected before your script was started through procfs:

output_dest=$(readlink -f /dev/fd/1)

echo "My output is being written to $output_dest"

This is literally interrogating where your first file descriptor (which is stdout) is open to. Note that the results won't always be useful -- if your program is being piped into something else, for instance, it might be something like [pipe: 12345] .

If you care about portability or robustness, you should generally write your software in such a way that it doesn't need to know or care where its stdout is being directed.

---

The Best Practice: Redirecting Your Script's Stdout Yourself

Better practice, if you need an output filename that your script can access, is to accept that as an explicit argument:

#!/bin/sh
#      ^^ note that that makes this a POSIX sh script, not a bash script

outfile=$1

exec >"$outfile"  # all commands below here have their output written to outfile

cat >>EOF
This is written to $outfile
EOF

...and then directing the user to pass the filename as an argument:

./yourscript outfile

Answer 2

#!/bin/sh
outfile=$1
cat  << EOF > "$outfile"
echo "stuff"
EOF

With

./script.sh output.txt

You write to the file output.txt

Setting a default value, in case the user doesn't pass an argument, is left for a different question.