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Python argparse与stdin互斥,是选项之一

[英]Python argparse mutually exclusive with stdin being one of the options

I would like my script to receive these mutually exclusive input options: 我希望我的脚本接收以下互斥的输入选项:

  • an input file containing a JSON ( script.py -i input.json ); 包含JSON的输入文件( script.py -i input.json );
  • a string containing a JSON ( script.py '{"a":1}' ); 包含JSON的字符串( script.py '{"a":1}' );
  • a JSON from stdin ( echo '{"a":1}' | script.py or cat input.json | script.py ). 来自stdin的JSON( echo '{"a":1}' | script.pycat input.json | script.py )。

and these mutually exclusive output options : 这些互斥的输出选项

  • an output file containing a JSON; 包含JSON的输出文件;
  • a JSON in stdout. 标准输出中的JSON。

So I tried with this code 所以我尝试了这段代码

import json,sys,argparse
parser = argparse.ArgumentParser(description='Template for python script managing JSON as input/output format')

group = parser.add_mutually_exclusive_group()
group.add_argument('--input-file', '-i',  type=str, help='Input file name containing a valid JSON.', default=sys.stdin)
group.add_argument('json',    nargs='?',  type=str, help='Input string containing a valid JSON.' , default=sys.stdin)
parser.add_argument('--output-file', '-o',type=str, help='Output file name.')

args = parser.parse_args()

if not sys.stdin.isatty():
    data = sys.stdin.read()
else:
#    args = parser.parse_args()
    if args.input_file :
        data=open(args.input_file).read()
    elif args.json :
        data=args.json


datain=json.loads(data)

dataout=json.dumps(datain, indent=2)

if args.output_file :
        output_file=open(args.output_file, 'w')
        output_file.write(dataout+'\n')
        output_file.close()
else:
    print (dataout)

But it does not work with stdin as it requires at least one of the two group options. 但是它不适用于stdin,因为它至少需要两个group选项之一。

How can I add stdin in the list of input options? 如何在输入选项列表中添加标准输入?

Adding the default=sys.stdin argument works if I call it like that 如果我这样命名,则添加default=sys.stdin参数是default=sys.stdin

echo '{}' | ./script.py -

but not like that: 但不是这样的:

echo '{}' | ./script.py

I would take advantage of argparse.FileType with a default value of sys.stdin . 我会利用argparse.FileType的默认值sys.stdin

import json,sys,argparse
parser = argparse.ArgumentParser(description='Template for python script managing JSON as input/output format')

group = parser.add_mutually_exclusive_group()
group.add_argument(
    '--input-file', '-i',
    type=argparse.FileType('r'),
    default=sys.stdin,
    help='Input file name containing a valid JSON.')
group.add_argument(
    'json',
    nargs='?',
    type=str,
    help='Input string containing a valid JSON.')
parser.add_argument(
    '--output-file', '-o',
    type=argparse.FileType('w'),
    help='Output file name.',
    default=sys.stdout)

args = parser.parse_args()
data = args.json or args.input_file.read()

datain=json.loads(data)
dataout=json.dumps(datain, indent=2)
args.output_file.write(dataout)

With: 附:

group.add_argument('--input-file', '-i')

You could test 你可以测试

if args.input_file is None:
   <-i wasn't supplied>
else:
    if args.input_file == '-':
        f = sys.stdin
    else:
        f = open(args.input_file)
    data = f.read()  # etc

Or may be better: 或者可能更好:

    if args.input_file == '-':
        data = sys.stdin.read()
    else
        with open(args.input_file) as f:
            f.read()

A tricky thing with stdin is that you don't want to close it after use like you would with a regular file name. 使用stdin一个棘手的事情是,您不想像使用常规文件名一样在使用后关闭它。 And you can't use it in a with . 并且您不能在with使用它。

Similarly with stdout . stdout类似。

Some code sets a flag when it opens a file, as opposed to receiving an already open one, so it can remember to close the file at the end. 某些代码在打开文件时会设置一个标志,而不是接收一个已经打开的文件,因此它可以记住在最后关闭文件。

group.add_argument('--input-file','-i',nargs='?', default=None, const=sys.stdin)

would set arg.input_file to stdin when given -i without an argument. 给定-i不带参数时,会将arg.input_file设置为stdin But I think looking for a plain - string is a better idea. 但是我觉得找一个普通的-字符串是一个更好的主意。

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