在一个函数中创建多个文件，但它们相互覆盖。 的PHP

Question

I am in the process of creating a section of a webpage where a user can upload a photo then manipulate the attributes of said picture, title, caption, etc. My questions comes as this: I have an edit picture function that I create a new caption file in by

//create new file
$file = fopen($newinfofile,"w");

//write to file
fwrite($file,$caption);

//close the file
fclose($file);  

newinfofile being the files name.

I also create a new title file the same way but with different names

//create new file for title
$file2 = fopen($newinfofile2,"w");

//write to file for title
fwrite($file2,$newtitle);   

//close the file for title
fclose($file2);

Later I echo the contents of each file but my problem is that they are echoing the same thing, if I reverse the order and create my title file first they both echo caption info instead.

So in PHP can you not create and write to two files within the same function? Perhaps I am mis-understanding something but I am unsure as to what.

Edit "sharing the entire function"

//edit file name, picture title, picture caption

function EditRecord($dir, $collection,$picture,$newname,$newtitle,$caption)
{

    //set the picture paths

    $picpath = $dir . $collection . "/" . $picture;
    $newpicpath = $dir . $collection . "/" . $newname;

    //set name of file for caption info by changing out JPG for PHP
    $infofile = $dir . "Info/" . str_replace("jpg","php", $picture);
    $newinfofile = $dir . "Info/" . str_replace("jpg","php", $newname);

    //set name of file for title info by changing out JPG for PHP
    $infofile2 = $dir . "Info/" . str_replace("jpg","php", $picture);
    $newinfofile2 = $dir . "Info/" . str_replace("jpg","php", $newname);

    //replace \r with <br>
    $caption = str_replace("\r","<br>", $caption);

    //rename picture JPG file
    rename($picpath, $newpicpath);

    //rename info PHP file
    rename($infofile, $newinfofile);

    //rename 2nd info php file for title
    rename($infofile2, $newinfofile2);

    //create new file
    $file = fopen($newinfofile,"w");

    //write to file
    fwrite($file,$caption);

    //close the file
    fclose($file);  

    //create new file for title
    $file2 = fopen($newinfofile2,"w");

    //write to file for title
    fwrite($file2,$newtitle);   

    //close the file for title
    fclose($file2); 
}

Answer 1

The two filesnames you create are exactly the same.

$newinfofile = $dir . "Info/" . str_replace("jpg","php", $newname);

$newinfofile2 = $dir . "Info/" . str_replace("jpg","php", $newname);

both variables will contain the same filename and so write to the same file, consequently overwriting.

Answer 2

You actually generate same file names in $newinfofile and $newinfofile2 :

//set name of file for caption info by changing out JPG for PHP
$infofile = $dir . "Info/" . str_replace("jpg","php", $picture);
$newinfofile = $dir . "Info/" . str_replace("jpg","php", $newname);

is same as

//set name of file for title info by changing out JPG for PHP
$infofile2 = $dir . "Info/" . str_replace("jpg","php", $picture);
$newinfofile2 = $dir . "Info/" . str_replace("jpg","php", $newname);