Python：将列表项写入文本文件

Question

I'm writing the content from one column in a rather large Excel file into separate text files using xlrd , one text file for each row in the column. In total, I have 1312 rows in the column, meaning I hope to get 1312 text files.

This should be trivial. I manage just fine to save all the individual Excel cells from the colum into a Python list of 1312 items. But for some reason when I run the code it only copies 619 out of 1312 list items into text files. I don't get an error message, the code compiles successfully, it just refuses to create the remaining files. It's also always 619 files that it creates, never more, never less.

Here is my code (The date is for naming the files after the date, which is another column in the Excel file. I made the datelist to check if it was perhaps not saving that part, but it is):

import xlrd
import os

path = r'C:\Users\data'
file = "data.xlsx"

os.chdir(path)

book = xlrd.open_workbook(file)
sheet = book.sheet_by_index(0)
contentlist=[]
datelist=[]
for row in sheet.get_rows():
    date = str(row[5].value)
    datelist.append(date)
    content = str(row[7].value)
    contentlist.append(content)

    for item in datelist:
        filename = item + ".txt"
    for item in contentlist:
        with open(filename, 'w', encoding='utf-8') as f:
            f.write(str(item))

Answer 1

That code just looks completely wrong.

I guess what you mean is:

for row in sheet.get_rows():
    name, content = str(row[5].value), str(row[7].value)
    with open(name + ".txt", 'w', encoding='utf-8') as f:
        f.write(content)