XPath查询：使用条件获取特定值

Question

I make a JAVA program to parse xml file like this exemple :

<lom:contribute>
        <lom:role>
            <lom:source>LOMv1.0</lom:source>
            <lom:value>author</lom:value>
        </lom:role>
        <lom:entity>toto</lom:entity>
        <lom:date>
            <lom:dateTime>2009-10-07</lom:dateTime>
        </lom:date>
    </lom:contribute>
    <lom:contribute>
        <lom:role>
            <lom:source>LOMv1.0</lom:source>
            <lom:value>instructional designer</lom:value>
        </lom:role>
        <lom:entity>titi</lom:entity>
        <lom:date>
            <lom:dateTime>2009-10-07</lom:dateTime>
        </lom:date>
    </lom:contribute>

I would like to make XPath query to get the entity (toto in this exemple) when the role value is author. I have make this query for the moment : //*[local-name()='contribute']/*[local-name()='role']/*[local-name()='value'] = 'author' . This query return true if author was present in file but I don't know how to get entity value. Thanks in advance.

Answer 1

This XPath returns toto :

//*[local-name()='contribute'][*[local-name()='role']/*[local-name()='value'] = 'author']/*[local-name()='entity']/text()

If you remove the last /text() , it returns the entity element containing the text toto . I'm not sure which of them are you looking for.