无法在C函数中使用int *的值

Question

I'm having some trouble while trying to use the value of a int variable inside a function; a variable that I need to change inside the function, so I passed it as a int * variable, and when calling the function simply passing the address of that variable like functionName(&variable);

But i'm having problems, and I have no idea of why i'm getting error while trying to compile it. (I'm using debian 9)

my function is here:

void subvetcont(int * vetor, int tam, int * vetresult, int * tamresult){
  int incmaior=0;
  int fimmaior=0;
  int incaux=incmaior;
  int fimaux=fimmaior;

  *tamresult = 0;

  for(int i=1; i < tam; i++){
      if(vetor[i] == vetor[i-1]+1) fimaux=i;
      else if((fimaux-incaux) > (fimmaior - incmaior)){
          incmaior = incaux;
          fimmaior = fimaux;
          incaux=i;
          fimaux=i;
      }
      else{
        incaux = i;
        fimaux = i;
      }
  }
  for(int i=incmaior, tamresult=0; i <= fimmaior; i++){
      vetresult[(*tamresult)] = vetor[i];
      (*tamresult) = (*tamresult) + 1;
  }
}

what I got is

ex4.c: In function ‘subvetcont’:
ex4.c:104:14: error: invalid type argument of unary ‘*’ (have ‘int’)
   vetresult[(*tamresult)] = vetor[i];
              ^~~~~~~~~~
ex4.c:105:4: error: invalid type argument of unary ‘*’ (have ‘int’)
   (*tamresult) = (*tamresult) + 1;
                   ^~~~~~~~~~
ex4.c:105:19: error: invalid type argument of unary ‘*’ (have ‘int’)
   (*tamresult) = (*tamresult) + 1;
                   ^~~~~~~~~~

Am I using pointers wrong?

Answer 1

You've declared a new variable tamresult in the for loop:

for (int i = incmaior = 0, tamresult = 0; i < fimmaior; i++) {
    ...
}

Within the loop, tamresult is that int variable, not the int* parameter to the function, so you can't indirect through it.

I'm not sure why you put that there. You already assigned *tamresult = 0; earlier in the function, there's no need to assign to it in the for header. Just remove it.

for (int i = incmaior = 0; i < fimmaior; i++) {
    ...
}