获取元组列表中的最大值

Question

I have a list of tuples:

card_list= [(2, (1, S)), (0, (12, H)), (1, (5, C)]

This list contains cards: (cardindex, (value, suit)) where cardindex is a index to store the position of the card but irrelevant for this my particular question.

So in the example there are 3 cards in the list:

• (2, (1, S)) = Ace of Spades with an index of 2.
• (0, (12, H)) = King of Hearts with an index of 0
• (1, (5, C)) = 5 of Clubs with index 1

Well, my question is: I desire to obtain the item with the max value, this is, i have to get the item: (0, (12, H))

My attempt is:

CardWithHighestValue= max(card_list,key=itemgetter(1)[0])

But I get the item or the value? And the most important: is it really correct that sentence?

Thanks in advance.

Answer 1

replace

CardWithHighestValue= max(card_list,key=itemgetter(1)[0])

with

CardWithHighestValue= max(card_list,key=itemgetter(1))

Demo

from operator import itemgetter
card_list= [(2, (1, "S")), (0, (12, "H")), (1, (5, "C"))]
print max(card_list,key=itemgetter(1)) 

card_list= [(2, (1, "S")), (0, (4, "H")), (1, (5, "C"))]
print max(card_list,key=itemgetter(1))

Output:

(0, (12, 'H'))
(1, (5, 'C'))

Answer 2

You can also use an anonymous function as key:

Demo:

print(max(card_list, key=lambda x:x[1]))

Output:

(0, (12, 'H'))

Answer 3

Try this:

lst=[(1,('a',10)), (2,('b',10)),(10,('a',10)), (3,('a',10))]

So

print("min: ", min(lst)[0]) # min: 1

And

print("max: ", max(lst)[0]) # max:  10