Python：遍历字符串并仅打印特定单词

Question

I'm taking a class in python and now I'm struggling to complete one of the tasks.

The aim is to ask for an input, integrate through that string and print only words that start with letters > g. If the word starts with a letter larger than g, we print that word. Otherwise, we empty the word and iterate through the next word(s) in the string to do the same check.

This is the code I have, and the output. Would be grateful for some tips on how to solve the problem.

        # [] create words after "G" following the Assignment requirements use of functions, menhods and kwyowrds
        # sample quote "Wheresoever you go, go with all your heart" ~ Confucius (551 BC - 479 BC)
        # [] copy and paste in edX assignment page

        quote = input("Enter a sentence: ")
        word = ""

        # iterate through each character in quote
        for char in quote:

            # test if character is alpha
            if char.isalpha():
                word += char 

            else:


                if word[0].lower() >= "h":
                    print(word.upper())   

                else:
                    word=""

    Enter a sentence: Wheresoever you go, go with all your heart
    WHERESOEVER
    WHERESOEVERYOU
    WHERESOEVERYOUGO
    WHERESOEVERYOUGO
    WHERESOEVERYOUGOGO
    WHERESOEVERYOUGOGOWITH
    WHERESOEVERYOUGOGOWITHALL
    WHERESOEVERYOUGOGOWITHALLYOUR



The output should look like,

Sample output:
WHERESOEVER
YOU
WITH
YOUR
HEART

Answer 1

Simply a list comprehension with split will do:

s = "Wheresoever you go, go with all your heart"
print(' '.join([word for word in s.split() if word[0].lower() > 'g']))
# Wheresoever you with your heart

Modifying to match with the desired output (Making all uppercase and on new lines):

s = "Wheresoever you go, go with all your heart"
print('\n'.join([word.upper() for word in s.split() if word[0].lower() > 'g']))

'''
WHERESOEVER 
YOU 
WITH 
YOUR 
HEART
'''

Without list comprehension:

s = "Wheresoever you go, go with all your heart"
for word in s.split():  # Split the sentence into words and iterate through each.
    if word[0].lower() > 'g':  # Check if the first character (lowercased) > g.
        print(word.upper())  # If so, print the word all capitalised.

Answer 2

s = "Wheresoever you go, go with all your heart"
out = s.translate(str.maketrans(string.punctuation, " "*len(string.punctuation)))
desired_result = [word.upper() for word in out.split() if word and word[0].lower() > 'g']
print(*desired_result, sep="\n")

Answer 3

Here is a readable and commented solution. The idea is first to split the sentence into a list of words using re.findall (regex package) and iterate through this list, instead of iterating on each character as you did. It is then quite easy to print only the words starting by a letter greater then 'g':

import re

# Prompt for an input sentence
quote = input("Enter a sentence: ")

# Split the sentence into a list of words
words = re.findall(r'\w+', quote)

# Iterate through each word
for word in words:
    # Print the word if its 1st letter is greater than 'g'
    if word[0].lower() > 'g':
        print(word.upper())

To go further, here is also the one-line style solution based on exactly the same logic, using list comprehension:

import re

# Prompt for an input sentence
quote = input("Enter a sentence: ")

# Print each word starting by a letter greater than 'g', in upper case
print(*[word.upper() for word in re.findall(r'\w+', quote) if word[0].lower() > 'g'], sep='\n')

Answer 4

Your problem is that you're only resetting word to an empty string in the else clause. You need to reset it to an empty string immediately after the print(word.upper()) statement as well for the code as you've wrote it to work correctly.

That being said, if it's not explicitly disallowed for the class you're taking, you should look into string methods, specifically string.split()