[英]close a pop up and reload another pop up
I am new to javascript and all so pardon me for the mistakes. 我是javascript新手,所以请原谅我的错误。 I am trying to open a pop up for some device discovery.
我正在尝试打开用于某些设备发现的弹出窗口。 When clicked on the below div,
当点击下面的div时,
<div class="ui-grid-solo">
<div class="ui-block-a">
<a href="#waitDiscoveryDialog" data-rel="popup"
data-position-to="window" data-transition="pop"
class="ui-btn ui-corner-all ui-shadow ui-btn-a"
>Discover Device ...</a>
</div>
</div>
it opens a pop up like this 它会像这样打开一个弹出窗口
<div data-role="popup" id="waitDiscoveryDialog" data-overlay-theme="b" data-theme="b"
data-dismissible="false" style="max-width:400px;">
<div data-role="header" data-theme="a">
<h1>Device Discovery</h1>
</div>
<div role="main" class="ui-content">
<h3 class="ui-title"
>This will search for new Devices.</h3>
<a href="#" class="ui-btn ui-corner-all ui-shadow ui-btn-inline ui-btn-b"
data-rel="back">Cancel</a>
<input type="button" data-theme="b" data-inline="true" value="Discover"
onClick="var hi=document.createElement('input');
hi.type='hidden'; hi.name='action'; hi.value='Discover';
settings_form.appendChild(hi);
settings_form.submit();">
</div>
</div>
My requirement is to send the hi.name='action'; 我的要求是发送hi.name ='action'; and hi.value='Discover' without the input button in the pop up.
和hi.value ='Discover',在弹出窗口中没有输入按钮。 Because I am using flask framework and there i use this code
因为我使用的是Flask框架,所以我使用了这段代码
if request.method == 'POST':
rf = request.form
try:
action = request.form["action"]
except:
action = ""
if "Discover" == action:
//code for discovering the device
Then close this pop up and open another pop up with a status like "Device found or not found". 然后关闭此弹出窗口,然后打开另一个状态为“找到或未找到设备”的弹出窗口。 Can anyone help me to solve this.?
谁能帮我解决这个问题。 Thanks in advance..
提前致谢..
As I can see in your code, there is no user input in the popup and you want to submit a static value. 正如我在您的代码中看到的那样,弹出窗口中没有用户输入,您想提交一个静态值。 If this is the case, why do you even need to open a popup when it is not doing anything?
如果是这种情况,为什么您甚至在不执行任何操作时还需要打开一个弹出窗口?
You can simply write a function triggered on click of button that opens the popup as of now and submit the form. 您可以简单地编写一个单击按钮触发的函数,该函数从现在开始打开弹出窗口并提交表单。
After submission, you can continue your function to open a popup for "Device found or not found" 提交后,您可以继续您的功能以打开“找到或找不到设备”的弹出窗口
For example: 例如:
<div class="myPopup">
<h1>This is my popup</h1>
</div>
<style>
.myPopup {
display: none;
position: fixed;
top: 0px;
bottom: 0px;
top: 0px;
bottom: 0px;
margin: auto;
border: 1px solid black;
border-radius: 5px;
height: 500px;
width: 500px;
}
.showPopup {
display: inline-block;
}
</style>
<button title="This will search for new devices" onclick="submitForm()">Discover</button>
function submitForm() {
var hi=document.createElement('input');
hi.type='hidden'; hi.name='action'; hi.value='Discover';
settings_form.appendChild(hi);
settings_form.submit();
}
settings_form[0].addEventListener("submit", function() {
document.getElementsByClassName("myPopup")[0].classList.add("showPopup");
});
Let me know if this helps. 让我知道是否有帮助。
请试试
<input type="button" data-theme="b" data-inline="true" onClick="var settings_form= $('formid'); settings_form.submit('Discover');">
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