如何在C ++中跳过读取CSV文件的第一列

Question

Below code is to get some data from csv file. But the result is showing as follow:

5,Jones,123-123-1234,BCBS,GP1234,39,Sarah,Broken Arm,3

6,Smith,123-231-1234,UHC,G1234,47,Francine,Physical Therapy,03/25/2015

9,Adams,123-123-4321,Cigna,U1234,28,Bob,Broken Arm,2

5,Van Gogh,123-321-1234,BCBS,GP1235,37,Andrea,Tummy Ache,3

10,Pewterschmidt,123-312-1234,UHC,G1112,42,Peter,Supervision normal first pregnancy,03/26/2015

But I want to get the data except first column(such as 5,6,9,5,10) How can I do that? Could you give me an idea? Thanks.

void Hospital::readRecordsFile()
{
    fileName = "Waterbury Hospital patients records.csv";
    ifstream file(fileName);
    string value;
    vector <string> getInform;
    while(file.good())
    {
        getline(file, value);
        getInform.push_back(value);
        //getInform.erase(getInform.begin()+1);
    }

    for(int i=0;i<getInform.size();i++)
    {
        cout << getInform[i] << endl;
    }

}

Answer 1

You can find first separator (,) in each line and then delete all charaters before it:

getline(file, value);
const auto pos = value.find(',');
if(pos != string::npos)
    value.erase(0, pos + 1);

If you are not sure about used separator character (,) in CSV file. You would probably do ignore all digits from the beginning of each line:

getline(file, value);
const auto pos = value.find_first_not_of("0123456789");
if(pos != string::npos)
    value.erase(0, pos + 1);

Answer 2

std::istream::ignore can be used to ignore some of the text from an input stream.

Extracts and discards characters from the input stream until and including delim .

file.ignore(std::numeric_limits<std::streamsize>::max(), ',');

and follow it up with getline to read the rest of the line.

getline(file, value);

Answer 3

You should split each line by ',' and then ignore the first part.

Simply parse string to rich the first ',' character, then use substring from that index to end.