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SyntaxError:位置17的JSON中的意外令牌S

[英]SyntaxError: Unexpected token S in JSON at position 17

In a product warranty registration, there is a syntax error in JSON.parse() but I can not find this error. 在产品保修注册中, JSON.parse()存在语法错误,但我找不到此错误。 this is the first application in AngularJS that I am doing, usually I program in Java. 这是我正在AngularJS中进行的第一个应用程序,通常我使用Java进行编程。 I have an API developed in PHP that does the Back-end, and a controller that makes the communication between the API and the view. 我有一个用PHP开发的API,它执行后端操作,还有一个控制器,用于在API和视图之间进行通信。

My controller: 我的控制器:

function adicionarGarantiaCtrl(
    $scope,
    $rootScope,
    constants,
    connectServerFactory
    ngDialog
) {
    var METHOD_GET;
    var METHOD_POST;
    var URL_ADICIONAR_LINK_GARANTIA;

    init();
    function init() {
        METHOD_GET = constants.METHOD_GET();
        METHOD_POST = constants.METHOD_POST();
        URL_ADICIONAR_LINK_GARANTIA = constants.URL_ADICIONAR_LINK_GARANTIA();
    }

    $scope.salvarGarantia = function() {
        var salvar = {
            "ano": $scope.add_ano,
            "mes": $scope.add_mes,
            "link": $scope.add_link,
            "num_mes": $scope.add_nmes
        };

        console.log("TESTE adicionarGarantiaCtrl");
        console.log(salvar);

        connectServerFactory.conectar(
            METHOD_POST,
            URL_ADICIONAR_LINK_GARANTIA,
            salvar,
            function(data) {
                console.log(data);
                $rootScope.garantia_ano = data.ano;
                $rootScope.garantia_mes = data.mes;
                $rootScope.garantia_link = data.link;
                $rootScope.garantia_num_mes = data.num_mes;
            },
            function(erro) {
                console.log(erro);
            }
        );

        ngDialog.close();
    }
}

My API.. 我的API

function adicionar_garantia() {
    $request = \Slim\Slim::getInstance()->request();
    $garantia = json_decode($request->getBody());

    $sql = "INSERT INTO garantia(" .
        "garantia, troca_distribuidor, garantia_fabrica, garantia_antecipada" .
    ") VALUES (" .
        ":garantia, :troca_distribuidor, :garantia_fabrica, :garantia_antecipada" .
    ")";

    try {
        $db = getDB();
        $stmt = $db->prepare($sql);
        $stmt->bindParam("garantia", $garantia->garantia);
        $stmt->bindParam("troca_distribuidor", $garantia->troca_distribuidor);
        $stmt->bindParam("garantia_fabrica", $garantia->garantia_fabrica);
        $stmt->bindParam("garantia_antecipada", $garantia->garantia_antecipada);
        $stmt->execute();
        $garantia->id_garantia = $db->lastInsertId();
        $db = null;
        echo json_encode($garantia);
    } catch(PDOException $e) {
        echo '{"error":{"text":'. $e->getMessage() .'}}';
    }
}

The issue you're having here is the JSON in the catch block is not quoting the message. 您在这里遇到的问题是catch块中的JSON没有引用消息。 The following line: 下一行:

echo '{"error":{"text":'. $e->getMessage() .'}}';

Should become: 应该变成:

echo '{"error":{"text":"'. $e->getMessage() .'"}}';

Perhaps a better option would be to continue using the json_encode function as you did in the try section of the try catch . 也许更好的选择是像在try catchtry部分中那样继续使用json_encode函数。 This is both (In my opinion) easier to debug, and easier to read. (在我看来)这既易于调试,又易于阅读。

echo json_encode(array(
    'error' => array(
        'text' => $e->getMessage()
    )
));

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