在 es6 中解构对象数组

Question

In es6, how can i simplify the following lines using destructuring?:

const array0 = someArray[0].data;
const array1 = someArray[1].data;
const array2 = someArray[2].data;

Answer 1

In es6, how can i simplify the following lines using destructuring?:

const array0 = someArray[0].data;
const array1 = someArray[1].data;
const array2 = someArray[2].data;

Answer 2

In es6, how can i simplify the following lines using destructuring?:

const array0 = someArray[0].data;
const array1 = someArray[1].data;
const array2 = someArray[2].data;

Answer 3

In es6, how can i simplify the following lines using destructuring?:

const array0 = someArray[0].data;
const array1 = someArray[1].data;
const array2 = someArray[2].data;

Answer 4

In es6, how can i simplify the following lines using destructuring?:

const array0 = someArray[0].data;
const array1 = someArray[1].data;
const array2 = someArray[2].data;

Answer 5

@Daniel, I presume you were looking to destructure a nested Object in an array of Objects. Following @nem035 was able to extract the nested Object's property using his pattern.

What is happening is that you're first extracting each object from addresses array then destructuring each object by extracting its properties and renaming it including the nested Object:

 addresses = [ { locality:"Sarjapura, Bangalore", coordinates:{latitude:"12.901160", longitude:"77.711680"} }, { locality:"Vadakara, Kozhikode", coordinates:{latitude:"11.588980", longitude:"75.596450"} } ] const [ {locality:loc1, coordinates:{latitude:lat1, longitude:ltd1}}, {locality:loc2, coordinates:{latitude:lat2, longitude:ltd2}} ] = addresses console.log(`Latitude of Vadakara:: ${lat2}`)