线程“主”中的异常NumberFormatException

Question

Exception in thread "main" java.lang.NumberFormatException: For input string: "1001"

I dont understand why this code throws exception.

1001 elma 87 --> This is the text file and I'm sure this is a number.

public class Food {
    public String[][] foodArray = new String[1000][100];
    public int sayac = 0;

    public void readText() {
      try (Scanner sc = new Scanner(new BufferedReader(new FileReader("food.txt")))) {
        while (sc.hasNextLine()) {
            String bilgiler = sc.nextLine().trim();
            foodArray[sayac] = bilgiler.split("\t");
            System.out.println(Integer.parseInt(foodArray[sayac][0]));
            sayac++;
        }
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }
}

}

Exception in thread "main" java.lang.NumberFormatException: For input string: "1001"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
at Food.readText(Food.java:13)
at Main.main(Main.java:11)

Answer 1

The only problem that I can see that in the file the character that is separating the words is not a tab (\\t) character, but maybe just spaces. That's why it is not able to split the line correctly. Can you show us what the exact stack trace is?

Answer 2

Delimiting character is not tab(\\t) which is why the line is not getting split in different parts and whole line is stored at 0th index of the array. And when you use parseInt it tries to parse the whole line which is 1001 elma 87

I would suggest using bilgiler.split(" ") which will take care of single or multiple spaces used as delimiter.

Answer 3

your file line separator might not be tabs, i advise you to print the split array and use bilgiler.split("\\\\s+"); to split all the spaces between words