如果dict中的值相等，则返回键python

Question

I have a dict of keys and values. I need to compare the values of all the keys if there are the same values in the dict and then return the keys, which have the same values.

b = {(1, 1): '4', (2, 1): '4',(3,1):'8',(4,2):'9',(2,4):'10'}
p = dict(zip(b.values(),b.keys()))

The output I'm getting:

{'4': (2, 1), '8': (3, 1), '9': (4, 2), '10': (2, 4)}

Expected output:

{(1, 1): '4', (2, 1): '4'}

Answer 1

A single liner using dict comprehension :

>>> {k:v for k, v in b.items() if list(b.values()).count(v) > 1}

Here to determine if other values also contain the same, we check for the count to be greater than one.

#driver values :

IN : b = {(1, 1): '4', (2, 1): '4',(3,1):'8',(4,2):'9',(2,4):'10'}
OUT : {(1, 1): '4', (2, 1): '4'}