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如何在Java中限制Hangman中的猜测数量

[英]How to limit the number of guesses in Hangman in Java

So i have my code working great. 所以我的代码运行良好。 I just need help in limiting the number of guesses. 我只需要帮助来限制猜测的数量。 And every time you make a wrong guess, to have a counter to tell you how many guesses you have left. 每次您做出错误的猜测时,都要有一个计数器来告诉您还剩下多少个猜测。

So I want to set the limit of guesses to 15. So every time you make an incorrect a bad guess counter displays to the user to (increase pressure/stress) 14 guesses left, or you lose. 因此,我想将猜测的上限设置为15。因此,每次输入错误时,都会向用户显示一个错误的猜测计数器,以(增加压力/压力)留下14个猜测,否则您将输掉。

Here's my code: 这是我的代码:

    import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;

public class Hangman {
    private final static int maxGuesses = 5;


    static ArrayList<String> words = new ArrayList<>();

        static boolean isCorrect;

        public static void main(String[] args) {

            // getting file
            File filename = new File("hangman.txt");
            if (!filename.exists()) {
                System.out.println(filename.getAbsolutePath());
                System.out.println(filename + " does not exist.");
                System.exit(1);
            }
            // reading word file
            try {
                Scanner input = new Scanner(filename);
                while (input.hasNext()) {
                    words.add(input.next());
                }
            } catch (FileNotFoundException ex) {
                ex.printStackTrace();
            }
            // debug: display words
            //System.out.println(words);

            Scanner input = new Scanner(System.in);
            String playStats = "y";
            while (playStats.equals("y")) {
                String word = getWord();
                String hiddenWord = getHiddenWord(word);
                int missCount = 0;


                    while (true) {
                    System.out.print("(Guess) Enter a letter in word " + hiddenWord + " > ");
                    char ch = input.next().charAt(0);

                    if (!isAlreadyInWord(hiddenWord, ch)) {

                        hiddenWord = getGuess(word, hiddenWord, ch);
                        if (missCount>maxGuesses){
                           // Print info on max guesses reached
                         System.out.println("you have reached" + missCount + "you have" + maxGuesses + 
                                 " left");
                           break;
                          }
                        if(word.equals(hiddenWord)) {

                        if (!isCorrect) {
                            System.out.println(ch + " is not in the word.");
                            missCount++;
                        }   
                    else {
                        System.out.println(ch + " is already in word.");
                    }
                        break;
                        } 
                        }
                    }
                System.out.println("The word is " + hiddenWord + " You missed " + missCount + " times");
                System.out.println("Do you want to guess another word? Enter y or n >");
                playStats = input.next();
            }

        }

        public static String getWord() {
            return words.get((int) (Math.random() * words.size()));
        }

        public static String getHiddenWord(String word) {

            String hidden = "";
            for (int i = 0; i < word.length(); i++) {
                hidden += "*";
            }
            return hidden;
        }

        static public String getGuess(String word, String hiddenWord, char ch) {

            isCorrect = false;
            StringBuilder s = new StringBuilder(hiddenWord);
            for (int i = 0; i < word.length(); i++) {

                if (ch == word.charAt(i) && s.charAt(i) == '*') {
                    isCorrect = true;
                    s = s.deleteCharAt(i);
                    s = s.insert(i, ch);
                }
            }
            return s.toString();
        }

        public static boolean isAlreadyInWord(String hiddenWord, char ch) {

            for (int i = 0; i < hiddenWord.length(); i++) {

                if (ch == hiddenWord.charAt(i)) {
                    return true;
                }
            }
            return false;
        }
    }

I'm assuming it has something to do with my "missCount" as the counter.... but how can i write in there that the missCount cannot exceed 15 tries and to display the number of tries? 我以为它与我的“ missCount”作为计数器有关系....但是我如何在其中写出missCount不能超过15次尝试并显示尝试次数?

Thanks in advance. 提前致谢。

Be aware that my suggestion is not an elegant solution. 请注意,我的建议不是一个明智的解决方案。

  • Create a static final maxGuesses with a value (eg 15). 创建一个带有值(例如15)的静态最终maxGuesses。
  • Change the while-condition from !word.equals(hiddenWord) to true . 将while条件从!word.equals(hiddenWord)更改为true This loop would now never terminate - unless we introduce break statements. 现在,此循环将永远不会终止-除非我们引入break语句。
  • Create a new check (if-condition) to see if the number of tries was exceeded (eg missCount>maxGuesses ). 创建一个新的检查(如果条件),以查看是否超过了尝试次数(例如missCount>maxGuesses )。 Print this information in the if-block and also add the break to exit the inner while. 在if块中打印此信息,并添加break以退出内部while。
  • Create another check (if-condition) with word.equals(hiddenWord) in - this is used to figure out if the word was found. 使用word.equals(hiddenWord)创建另一个检查(如果条件),用于检查是否找到了该词。 Print the information about the found word as part of the if-block and also add the break statement 打印有关找到的单词的信息作为if块的一部分,并添加break语句
  • Both checks should be part of the inner while-loop. 这两个检查都应该是内部while循环的一部分。

.

while (true) { 
  if (missedCount>maxGuesses){
   // Print info on max guesses reached
   break;
  }
  // Does the read input stuff
  if (word.equals(hiddenWord)){
   // Print info on word was guessed
   break;
  }
}

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