按整数（第一个字符）对字符串数组进行排序

Question

I am wondering how should be the easy way to solve this problem.

I have an array of strings, something like this:

Array [ "15 Some string", "16 Some string", "13 Some string", "11 Some string", "6 Some string", "8 Some string", "12 Some string", "5 Some string", "9 Some string", "10 Some string" ]

And I would like to sort it by integer, which is the first character of this array (and will be every time), using javascript . My desired output would be:

Array [ "16 Some string", "15 Some string", "13 Some string", "12 Some string", "11 Some string", "10 Some string", "9 Some string", "8 Some string", "6 Some string", "5 Some string" ]

Anyone can help?

Answer 1

How about simply parsing the string values to numbers

 var array = ["15 Some string", "16 Some string", "13 Some string", "11 Some string", "6 Some string", "8 Some string", "12 Some string", "5 Some string", "9 Some string", "10 Some string"]; array.sort((a, b) => parseFloat(b) - parseFloat(a)); console.log(array); 

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Answer 2

Use regex to get the numbers and after it compare the numbers.

 const array = [ "15 Some string", "16 Some string", "13 Some string", "11 Some string", "6 Some string", "8 Some string", "12 Some string", "5 Some string", "9 Some string", "10 Some string" ]; array.sort((a,b) => b.match(/\\d+/g) - a.match(/\\d+/g)); console.log(array); 

Answer 3

You could match the starting integer value and sort by the delta of it.

 function getN(s) { return s.match(/^\\d+/); } var array = ["15 Some string", "16 Some string", "13 Some string", "11 Some string", "6 Some string", "8 Some string", "12 Some string", "5 Some string", "9 Some string", "10 Some string"]; array.sort(function (a, b) { return getN(b) - getN(a); }); console.log(array); 

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