如何在C ++中初始化双指针结构数组？

Question

I have a structure like below,

struct myStruct
{
CString a;
int b;
CString c;
int d;
}

The char** array can be initialized as below,

char **choices = (char *[]){ "New Game", "Continue Game", "Exit" };

Similarly how to initialize double pointer structure array. My requirement is I should not do dynamic memory allocations using new or malloc.

I need below kind of initialization.

myStruct** arr ={
....
....
....
....
};

Answer 1

First create a few myStruct objects:

myStruct ms1;
myStruct ms2;

Then create an array of pointers to myStruct :

myStruct* pointerArray[] = {&ms1, &ms2};

Finally, you can take the pointer to first element of that array. This is your "double pointer struct array" without dynamic allocation.

myStruct** arr = pointerArray;

---

 char **choices = (char *[]){ "New Game", "Continue Game", "Exit" }; 

This line has a few problems.

Firstly, the initialization syntax that you use is ill-formed in C++. Compound literals are a C99 feature and are not in the C++ language.

Secondly, you convert string literals to non-const char* . String literals are const in C++, and such conversion from const to non-const is ill-formed (since C++11; prior to that the conversion was deprecated).