有Task的麻烦获得Task结果（无法将System.Threading.Task.Task隐式转换为string []）

Question

Task t = new Task(() => grabber.grab(link));

var x = Task.WhenAny(t, Task.Delay(TimeSpan.FromSeconds(3)));

if (x.Result != null)
{
    // error cannot implicitly convert System.Threading.Task.Task  to string[]
    string[] result = x.Result; 
    foreach (string item in result)
    {
        list.Add(item);
    }
}

The function grab is totally synchronous and returns a string array

Answer 1

You're checking the result from the x Task, which is the Task that can be either the same as t or the result of Task.Delay(TimeSpan.FromSeconds(3)) (provided you await it). You should be able to get the Result from t instead:

Task<string[]> t = new Task<string[]>(() => grabber.grab(link));
//   ^^^^^^^^  also defining what the t.Result should contain    

var x = await Task.WhenAny(t, Task.Delay(TimeSpan.FromSeconds(3)));
if (x == t){ // make sure that Task.WhenAny returned the t Task
{
    string[] result = t.Result; // get t's Result, not x
    foreach (string item in result)
    {
        list.Add(item);
    }
}

Created a small reproducable example here