Apache Camel与收件人列表的路由

Question

I'm trying to route messages dynamically with org.apache.camel.

Here's my code :

from("direct:messenger")
            .routeId("messenger-provider")
            .bean(messengerService, "process")
            .marshal().json(JsonLibrary.Jackson)
            .setHeader(Exchange.HTTP_METHOD, constant("POST"))
            .recipientList(header("access_token")).ignoreInvalidEndpoints()

And here's the part of my service class concerned :

    exchange.getIn().setHeader("access_token", messengerServiceEndpoint.getEndpointUri()+"?access_token="+accessToken);

In fact I want to add the access_token dynamically to the endpoint URI. But i can only get the token from the service class.

If anyone have some insights that would be great, thank you

Answer 1

I think what you are looking for is org.apache.camel.impl.JndiRegistry or org.apache.camel.impl.SimpleRegistry :

You can bind your objects to the registry and retrieve where you need.

http://camel.apache.org/registry.html

Check this link for creating SimpleRegistry and using in Java DSL:

http://preparationforinterview.com/preparationforinterview/camel-spring-bean-javadsl

Below is a stackoverflow question on creating JNDIRegistry:

camel - get jndi registry

If you are using Spring, then you can use ApplicationContextRegistry:

ApplicationContextRegistry registry = exchange.getContext().getRegistry(ApplicationContextRegistry.class);
Map<String,Object>map = (Map<String,Object>)registry.lookup("map");
map.put("objectVar", objectVar);

Have a map in your Spring config to load the objects:

<bean id="map" class="java.util.HashMap"></bean>

Retrieve the objects:

Map<String,Object> map = (Map<String,Object>)registry.lookup("map");
    Object1 o = (Object1) map.get("objectVar");