如何在mongodb中按周对文档进行分组

Question

How do i calculate the total hours spend by each user on the basis of week and my week start from Friday to Thursday .

Records

{
  "_id" : ObjectId("5a69cd076b2beec65fa900e9"),
  "clock_date" : ISODate("2018-01-13T00:00:00.000Z"),
  "clock_in_time" : "10:40:53",
  "clock_out_time" : "12:40:53", 
},
{
  "_id" : ObjectId("5a69cd076b2beec65fa900e9"),
  "clock_date" : ISODate("2018-01-12T00:00:00.000Z"),
  "clock_in_time" : "10:00:53",
  "clock_out_time" : "10:40:53", 
},
{
  "_id" : ObjectId("5a69cd076b2beec65fa900e9"),
  "clock_date" : ISODate("2018-01-20T00:00:00.000Z"),
  "clock_in_time" : "10:20:00",
  "clock_out_time" : "12:40:53", 
},
{
  "_id" : ObjectId("5a69cd076b2beec65fa900e9"),
  "clock_date" : ISODate("2018-01-21T00:00:00.000Z"),
  "clock_in_time" : "10:40:53",
  "clock_out_time" : "11:40:53", 
},

Result to be like

 {
  week:'Jan 05, 2018 to Jan 11, 2018'
  totalhourse : 4
 },
 {
  week:'Jan 12, 2018 to Jan 18, 2018'
  totalhourse : 2:23
 },

. . . . .

Answer 1

Summing up the total hours with this schema is going to be tough and we should have a lot of calculations, since you have captured the time in and time out as strings. To find the difference we need to segregate hours:minutes:seconds and then we have to find the difference.

"clock_in_time" : "10:40:53",
"clock_out_time" : "12:40:53",

Alternatively you can modify your schema to capture the in time and out time as Date with time stamp.

"clock_in_time" : ISODate("2018-01-13T10:40:53.123+05:30"),
"clock_out_time" : ISODate("2018-01-13T12:40:53.121+05:30"),

If this modification is done then you can use aggregation pipeline to get the desired result

In aggregation pipeline first

• Use $match and $and to filter the documents within the date range(here you can feed in week start date and week end date)

• then use $subtract with $project

Please note this query will give you only one week's result at a time

References:

Subtracting time

$match with $and operator