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simplexml_load_file()-从xml生成html菜单

[英]simplexml_load_file() - generate html menu out of xml

I'm trying to create a menu for a php-website out of a xml file. 我正在尝试从xml文件中为php网站创建菜单。 The XML-Structure is: XML结构是:

<?xml version="1.0" encoding="utf-8" ?>
<MenuRoot>
    <Menu id="home" text="Startseite" url="../overview.php"></Menu>
    <Menu id="system" text="System" url="../system.php">
        <SubMenu id="system_sub1" text="Allgemein" url="../tba.php"></SubMenu>
        <SubMenu id="system_sub2" text="Abmelden" url="../logout.php"></SubMenu>
    </Menu>
</MenuRoot>

My PHP Code looks like - this does not work: 我的PHP代码如下所示-这不起作用:

if(file_exists('/var/www/content/menu.xml')) {
$xml = simplexml_load_file('/var/www/content/menu.xml');
    foreach($xml->children() as $menu) {
        echo '<li><a href="'.$menu->Menu['url'].'">'.$menu->Menu['text'].'</a>';
        if(NULL !== $menu->children()):
            echo '<ul>';
            foreach($menu->children() as $submenu) {
                echo '<li><a href="'.$submenu->SubMenu['url'].'">'.$submenu->SubMenu['text'].'</a></li>';
            }
            echo '</ul>';
        endif;
        echo '</li>';
    }
}
else:
    write_log(sprintf("menu.xml not found"));
endif;

I tried some different methods and did the basic way like, which works: 我尝试了一些不同的方法,并做了一些基本的方法,如:

if(file_exists('/var/www/content/menu.xml')) {
$xml = simplexml_load_file('/var/www/content/menu.xml');
echo '<li><a href="'.$xml->Menu[0]['url'].'">'.$xml->Menu[0]['text']..'</a>';
}

what am I doing wrong with my loops and accessing variables in my not working example? 在不工作的示例中,循环和访问变量有什么问题?

thanks! 谢谢!

When you access $menu->Menu['url'] , $menu is already the Menu node, and should be $menu['url'] . 当您访问$menu->Menu['url']$menu已经是Menu节点,应为$menu['url']

You can access to your menu directly using $xml->Menu . 您可以使用$xml->Menu直接访问$xml->Menu Then you can use count() to check the number of children: 然后,您可以使用count()检查子级数:

$xml = simplexml_load_file('/var/www/content/menu.xml');
foreach($xml->Menu as $menu) {
    echo '<li><a href="'.$menu['url'].'">'.$menu['text'].'</a>';

    if (count($menu->SubMenu)) {

        echo '<ul>';
        foreach($menu->SubMenu as $submenu) {
            echo '<li><a href="'.$submenu['url'].'">'.$submenu['text'].'</a></li>';
        }
        echo '</ul>';

    }
    echo '</li>';
}

Outputs: 输出:

<li>
    <a href="../overview.php">Startseite</a>
</li>
<li>
    <a href="../system.php">System</a>
    <ul>
        <li><a href="../tba.php">Allgemein</a></li>
        <li><a href="../logout.php">Abmelden</a></li>
    </ul>
</li>

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