访问红宝石哈希的元素

Question

Ruby 2.15

I defined the following hash:

test = Hash.new
test["foo"] = {
  'id' => 5,
  'lobbyist_id' => 19,
  'organization_id' => 8
}

If I do

test.each do |t|
  print t["id"] 
end

I get:

TypeError: no implicit conversion of String into Integer
    from (irb):1571:in `[]'

How do I access the elements, using an each loop?

Answer:

test.each do |t|
   t.each do |t1|
     puts t1["id"]
   end  
end

Answer 1

With a Hash, iteration is made through key first, then value. So have your block use what you need.

test.each do |key|
  puts key
end

test.each do |key, value|
  puts key
  puts value
end

There are also

test.each_key do |key|
  puts key
end

test.each_value do |value|
  puts value
end

---

Sidenote: id is inside test["foo"] , so maybe you'd need 2 loops

---

To get id from your hash directly:

test["foo"]["id"]

test["foo"].each {|k, v| puts "#{k}: #{v}" }

Answer 2

In your example we assume you've previously done:

test = Hash.new

In your example variable test is a hash and foo is a key who's value contains a hash of key values. If you want to target those, you'll need to loop over them

test['foo'].each do |k,v|
  puts "my key is #{k}"
  puts "it's value is {v}
end

If you want to do both at the same time:

test.each do |k,v|
  puts "base hash key #{k}"
  puts "base hash value #{v}"
  v.each do |kk,vv|
    puts "key #{kk}"
    puts "value #{vv}"
  end
end