我们如何基于节点js中的另一个对象数组值对对象数组进行排序

Question

How can we sort the object array based on another object array value, like we have an object array:

var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}]

In this the index 1,2,3,4,5 are having the same value of the key "tEnd" ie, 3 and 1 so I just need to sort only those index on the basis of another object array

var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}]

Here the userID 597,605,617,553,616 are having the score value 85,95,85,100,95

so based on score, I want to sort my first array Output should be:

[{"userID":554,"tEnd":6},{"userID":605,"tEnd":3},{"userID":597,"tEnd":3},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":617,"tEnd":1},{"userID":596,"tEnd":0}]

Answer 1

You could take the delta of tEnd and find the score and take that delta.

 function getScore(uID) { return (_profsort.find(({ userID }) => userID === uID) || { score: 0 }).score; } var _userEnd = [{ userID: 554, tEnd: 6 }, { userID: 597, tEnd: 3 }, { userID: 605, tEnd: 3 }, { userID: 617, tEnd: 1 }, { userID: 553, tEnd: 1 }, { userID: 616, tEnd: 1 }, { userID: 596, tEnd: 0 }], _profsort = [{ userID: 596, score: 100 }, { userID: 616, score: 95 }, { userID: 553, score: 100 }, { userID: 617, score: 85 }, { userID: 605, score: 95 }, { userID: 597, score: 85 }, { userID: 554, score: 100 }]; _userEnd.sort(function (a, b) { return b.tEnd - a.tEnd || getScore(b.userID) - getScore(a.userID); }); console.log(_userEnd); 

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Answer 2

Use sort and find

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score; //method to get the score value based on userId

var output = _userEnd.sort( (a, b) => 
        (b.tEnd - a.tEnd) || 
           fnGetScore(b.userID) - fnGetScore(b.userID)) //compare tEnd first and if they are same, compare the score value

Demo

 var _userEnd = [{ "userID": 554, "tEnd": 6 }, { "userID": 597, "tEnd": 3 }, { "userID": 605, "tEnd": 3 }, { "userID": 617, "tEnd": 1 }, { "userID": 553, "tEnd": 1 }, { "userID": 616, "tEnd": 1 }, { "userID": 596, "tEnd": 0 }]; var _profsort = [{ "userID": 596, "score": 100 }, { "userID": 616, "score": 95 }, { "userID": 553, "score": 100 }, { "userID": 617, "score": 85 }, { "userID": 605, "score": 95 }, { "userID": 597, "score": 85 }, { "userID": 554, "score": 100 }]; var fnGetScore = uid => _profsort.find(s => s.userID == uid).score; var output = _userEnd.sort((a, b) => (b.tEnd - a.tEnd) || fnGetScore(b.userID) - fnGetScore(b.userID)) console.log(output); 

Answer 3

Create an object of score by userID using Array.reduce . Sort by tEnd , and if it's equal sort by the score you get from the sortObject by the userId :

 var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}] var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}] var sortObj = _profsort.reduce((r, o) => { r[o.userID] = o.score; return r; }, Object.create(null)); _userEnd.sort((a, b) => b.tEnd - a.tEnd || sortObj[b.userID] - sortObj[a.userID]); console.log(_userEnd);