如果不满足条件，功能什么都不返回？

Question

I've been using Zapier's Code Steps to write code that sends variable information to the same Webhook. I figured out how to do that when information needs to be sent however I only want the code to send the object(s) to the Webhook when the buy condition is true. If buy is not true I want it to return nothing.

if(coins[i].buy===true)
{
fetch('https://hooks.zapier.com/hooks/catch/974762/krbqch/', { method: 
'POST', body: "Coin:"+coins[i].coin +",Value:"+coins[i].currentValue 
+",Buy:" +coins[i].buy+",Sell:"+coins[i].sell+",Date:"+currentDate})
    .then(function(res) {
        return res.json();
    }).then(function(json) {
        console.log(json);
    }).then(function() {
    callback(callback(null, {}));
  })
  .catch(callback);
}

If the buy condition is false I will get an error of "Error: You must return a single object or array of objects." This is important because most of the time buy will be false. I realize that this is because there is no callback I just do not know what to put instead. So what should I return if buy is false in order to prevent an error?

Answer 1

Going by the error, Error: You must return a single object or array of objects.

Zapier expects you to return an object or array of objects at the end.

You are doing that for the buy === true condition with this statement - callback(callback(null, {}));

Try doing the same outside the conditional block, just add the same line - callback(null, {});

This will return the {} to Zapier and your code step should succeed even when the condition is false.

Your code would look like this

if(coins[i].buy===true)
{
fetch('https://hooks.zapier.com/hooks/catch/974762/krbqch/', { method: 
'POST', body: "Coin:"+coins[i].coin +",Value:"+coins[i].currentValue 
+",Buy:" +coins[i].buy+",Sell:"+coins[i].sell+",Date:"+currentDate})
    .then(function(res) {
        return res.json();
    }).then(function(json) {
        console.log(json);
    }).then(function() {
    callback(callback(null, {}));
  })
  .catch(callback);
}
callback(null, {});

More examples here: https://zapier.com/help/code-examples/#introductory-http-example

You might want to get a new webhook URL as it is now public and anyone can trigger it.

I would recommend using the code block below - (Notice changes to the callback statement and removal of one .then block.)

if(coins[i].buy===true)
{
fetch('https://hooks.zapier.com/hooks/catch/974762/krbqch/', { method: 
'POST', body: "Coin:"+coins[i].coin +",Value:"+coins[i].currentValue 
+",Buy:" +coins[i].buy+",Sell:"+coins[i].sell+",Date:"+currentDate})
    .then(function(res) {
        return res.json();
    }).then(function(json) {
        console.log(json);
        callback(null, {});
    }).catch(callback);
}
callback(null, {});