从Oracle表填充下拉列表

Question

I have to populate drop down list from an oracle table I have used following code but it gives an empty drop down list. 我必须从使用以下代码的oracle表中填充下拉列表，但是它提供了一个空的下拉列表。

  <!DOCTYPE html>
 <html>
<body>


 <p style="font-size:35px;"><b>History Trades</b></p>


 <form action="dat.php" method="post">
 Select Instrument :<select name="instument">

 <?php 
 $conn = oci_connect("cse", "mahesh123", "XE"); 
 $sql = 'SELECT symbol FROM symbols'; 
 $stid = oci_parse($conn, $sql); 
 $success = oci_execute($stid); 
 while ($row = oci_fetch_array($stid, OCI_RETURN_NULLS+OCI_ASSOC))  
 { 
 echo "<option value=\"countryname1\">" . $row['symbol'] . "</option>"; 
 } 
?>       
</select> 



 Start Date:
 <input type="date" name="bday1" >
 End Date:
 <input type="date" name="bday2" ><br><br>


 <input type="image" src="sub.jpg" alt="Submit" width="100" height="48">  


  </form>


 </body>
 </html>

Please help me with this, I need to do it in php code. 请帮我解决这个问题，我需要在php代码中完成。 please help me in the areas where I have the issue in the given code. 请在给定代码中出现问题的区域为我提供帮助。

Answer 1

Field names are upper case by default in Oracle, and array keys are case-sensitive in PHP, so: 在Oracle中，字段名称默认为大写，而在PHP中，数组键区分大小写，因此：

echo "<option value=\"countryname1\">" . $row['SYMBOL'] . "</option>";

Also, turn on error output in your PHP development environment. 另外，在您的PHP开发环境中打开错误输出。 That would have shown a Notice: Undefined index: symbol in ... message, allowing you to fix the problem quite quickly. 那将显示一条Notice: Undefined index: symbol in ...消息，使您可以非常迅速地解决问题。

从Oracle表填充下拉列表

问题描述

1 个解决方案

解决方案1
0 2018-03-31 19:59:40

从Oracle表填充下拉列表

问题描述

1 个解决方案

解决方案1 0 2018-03-31 19:59:40

解决方案1
0 2018-03-31 19:59:40