在我的应用程序的资产目录中列出所有文件和文件夹（以及子文件夹），并检查资产是文件还是文件夹

Question

I want to check if the asset in Assets directory of my Android App is a File or a Directory.

I have already tried every solution available anywhere on internet including StackOverflow.

Most of the solutions use

File myFile = new File(path);

then check for myFile.isDirectory(); or myFile.isFile();

But it works only if I have my files and directories anywhere else other than under the Assets directory.

Any suggestions will be highly appreciated.

Answer 1

Here is a solution to my problem that I found out working 100% listing all directories and files even sub-directories and files in subdirectories. It also works for multiple levels.

Note: In my case

1. Filenames had a . in them. ie .htm .txt etc
2. Directorynames did not have any . in them.

Note: about -- path --

1. to get all files and directories in Assets root folder

   String path = ""; // assets

2. or to get files and directories in a subfolder use its name as path

   String path = "html"; // <<-- assets/html

    listAssetFiles2(path); // <<-- Call function where required //function to list files and directories public void listAssetFiles2 (String path){ String [] list; try { list = getAssets().list(path); if(list.length > 0){ for(String file : list){ System.out.println("File path = "+file); if(file.indexOf(".") < 0) { // <<-- check if filename has a . then it is a file - hopefully directory names dont have . System.out.println("This is a folder = "+path+"/"+file); if(path.equals("")) { listAssetFiles2(file); // <<-- To get subdirectory files and directories list and check }else{ listAssetFiles2(path+"/"+file); // <<-- For Multiple level subdirectories } }else{ System.out.println("This is a file = "+path+"/"+file); } } }else{ System.out.println("Failed Path = "+path); System.out.println("Check path again."); } }catch(IOException e){ e.printStackTrace(); } 

   }

Thanks

Answer 2

Instead of letting a dot in a name determine what should happen you should check if it is a file or a directory. Make your own isDirectory(name) function by trying to open an InputStream for the file/directory. If you succeed it is a file. If you get an exception its a directory. Dont forget to close the stream when done.