Android意图：无论用户使用的是默认浏览器，都在Firefox中打开链接？

Question

I am trying to make an intent that will open com.mozilla.firefox with my link and ignoring the default intent handler for .ACTION_VIEW

My current logic is this:

        Uri uri = formatURL(url); //Turns my string into a URI formatted correctly

        final Intent intent = new Intent(Intent.ACTION_VIEW, uri);
        intent.setPackage("com.mozilla.firefox");

        contextActivity.startActivity(intent);

This seems like it should work, but instead does nothing (compared to removing line #3, which opens in Chrome, my default browser). Is it possible to specifically target another app for an intent?

Answer 1

Try using:

intent.setClassName("packageName", "className");

But it's better to query the activities that can open the intent and launch it

List<ResolveInfo> activities = packageManager.queryIntentActivities(intent,
                        PackageManager.MATCH_ALL);

 for (ResolveInfo info :
                activities) {
     if( info.activityInfo.packageName.contains("com.mozilla.firefox")){
           //launch firefox: 
          intent.setClassName(info.activityInfo.packageName,info.activityInfo.name);
          startActivity(intent);         
          }
 }

so if Firefox is not installed you can start your default intent.