[英]Xamarin.forms event on leaving/changing the page
I'm looking for something like a function 我正在寻找像功能一样的东西
protected override void OnDisappearing()
{
}
in Xamarin Forms. 在Xamarin表格中。 The problem is that this feature is called even when I turn off the phone display. 问题是即使关闭手机显示屏也会调用此功能。 I'm looking for a feature that only responds to the event when the page is changed - for example, the user in the menu clicks on a page other than the one that is being visited. 我正在寻找一个仅在页面更改时响应事件的功能 - 例如,菜单中的用户单击正在访问的页面以外的页面。
thanks for your advice 谢谢你的建议
You will need to combine OnBackButtonPressed
and OnDisappearing
您需要结合OnBackButtonPressed
和OnDisappearing
OR OnAppearing
and OnDisappearing
或 OnAppearing
和OnDisappearing
You can create a base
page which implement OnBackButtonPressed
and or OnDisappearing
and or OnAppearing
. 您可以创建一个实现OnBackButtonPressed
和/或OnDisappearing
和/或OnAppearing
的base
页。
And you save "Active" page reference in a static variable. 并在静态变量中保存“活动”页面引用。
// this condition can help you concerning the screen on or off
if(this.Title == Activepage.Title) // or id
return;
What MVVM framework are you using? 你使用什么MVVM框架? There are typically events built into the viewmodel that you can leverage. 通常,视图模型中内置了可以利用的事件。
If you want the page to do something specific on a button press then I'd suggest putting the code in there. 如果您希望页面按下按钮上的特定内容,那么我建议将代码放在那里。
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