[英]Update the attribute value of an object using the map function in ES6
I am trying to code this in ES6.我正在尝试在 ES6 中对此进行编码。 Below is what I am trying to achieve.以下是我正在努力实现的目标。 Let's say I have an array of objects called schools
.假设我有一个名为schools
的对象数组。
let schools = [
{name: 'YorkTown', country: 'Spain'},
{name: 'Stanford', country: 'USA'},
{name: 'Gymnasium Achern', country: 'Germany'}
];
Now, I want to write a function called editSchoolName
which will take 3 parameters, schools
(which is the array I have defined above), oldName
and name
.现在,我想编写一个名为editSchoolName
的函数,它将接受 3 个参数, schools
(这是我在上面定义的数组)、 oldName
和name
。
I will pass the name of the school in the parameter oldName
and that name should be updated with the value in the parameter name
.我将在参数oldName
传递学校的名称,该名称应使用参数name
的值进行更新。
I don't want to change the state of the variable schools
so I am using a map
function which will return a new array with the changes.我不想更改变量schools
的状态,所以我使用了一个map
函数,它将返回一个包含更改的新数组。
The editSchoolName
function will be called like this - editSchoolName
函数将像这样被调用 -
var updatedSchools = editSchoolName(schools, "YorkTown", "New Gen");
Here, the name YorkTown
should be replaced with the name New Gen
.此处,名称YorkTown
应替换为名称New Gen
。 So the expected value of the array updatedSchools
should be -所以数组updatedSchools
的期望值应该是 -
let updatedSchools = [
{name: 'New Gen', country: 'Spain'},
{name: 'Stanford', country: 'USA'},
{name: 'Gymnasium Achern', country: 'Germany'}
];
This is how my editSchoolName function looks like -这就是我的 editSchoolName 函数的样子 -
const editSchoolName = (schools, oldName, name) =>
schools.map(item => {
if (item.name === oldName) {
/* This is the part where I need the logic */
} else {
return item;
}
});
Need help in making the change in the editSchoolName
function to achieve the above mentioned desired result.需要帮助在editSchoolName
函数中进行更改以实现上述预期结果。
You need to return the updated object: 您需要返回更新的对象:
const editSchoolName = (schools, oldName, name) =>
schools.map(item => {
if (item.name === oldName) {
return {...item, name};
} else {
return item;
}
});
const editSchoolName = (schools, oldName, newName) =>
schools.map(({name, ...school }) => ({ ...school, name: oldName === name ? newName : name }));
You could shorten it by using a ternary. 您可以使用三元缩短它。
try this, ES6 Object.assign()
to create copy of array element and update new object. 试试这个,ES6 Object.assign()
来创建数组元素的副本并更新新对象。
let schools = [{ name: 'YorkTown', country: 'Spain' }, { name: 'Stanford', country: 'USA' }, { name: 'Gymnasium Achern', country: 'Germany' } ]; const editSchoolName = (schools, oldName, name) => { return schools.map(item => { var temp = Object.assign({}, item); if (temp.name === oldName) { temp.name = name; } return temp; }); } var updatedSchools = editSchoolName(schools, "YorkTown", "New Gen"); console.log(updatedSchools); console.log(schools);
If you want to edit only the commented part: 如果您只想编辑注释部分:
const editSchoolName = (schools, oldName, name) =>
schools.map(item => {
if (item.name === oldName) {
var newItem = Object.assign({},item);
newItem.name = name;
return newItem;
}
else{
return item;
}
});
as simple as that:就如此容易:
const editSchoolName = ((schools, oldName, name) =>{
let results =schools.map((item,index) => {
if (item.name === oldName) {
let newItem = {...item, name}
return newItem;
} else {
return item;
}
});
return results;
});
I wonder how come none of the answers give simple solution 我想知道为什么没有答案给出简单的解决方案
const editSchoolName = (schools, oldName, newName) =>
schools.map(school => { if (school.name === oldName) school.name = newName;
return school;
});
let schools = [{ name: 'YorkTown', country: 'Spain' }, { name: 'Stanford', country: 'USA' }, { name: 'Gymnasium Achern', country: 'Germany' } ]; let updatedSchools = [{ name: 'New Gen', country: 'Spain' }, { name: 'Stanford', country: 'USA' }, { name: 'Gymnasium Achern', country: 'Germany' } ]; const editSchoolName = ((schools, oldName, name) =>{ schools.map(item => { if (item.name === oldName) { item.name = name; return item.name; } else { return item; } }); console.log(schools); }); editSchoolName(schools, 'YorkTown', "New Gen");
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