取平均值并再次通过列表。 计算大于平均值的数量和小于平均值的数量

Question

I'm trying to figure out the 2nd half of this question using python 3 but can't seem to figure it out. The first half of the code that I have is the following below...

A = [1,2,3,4] print(average(A)) 2.5

num = int(input('How many numbers: '))
total_sum = 0
for n in range(num):
    numbers = float(input('Enter number : '))
    total_sum += numbers
avg = total_sum/num
print('Average of ', num, ' numbers is :', avg)

number = int(input("Enter number: "))
if number < 2.5:
    print("Your number is smaller than 2.5")
else:
    print("Your number is greater than 2.5")

Answer 1

Save the numbers in list. Sort the list and check the number which is equivalent to or greater than an average number. U can then easily find the count of numbers less than and greater than avarage number.