错误C2440：&#39;初始化&#39;：无法从&#39;初始化列表&#39;转换为&#39;std :: vector <char *,std::allocator<_Ty> &gt;”

Question

I tried to compile the following codes:

vector<char*> art = { "a","an","the" };

but received error message:

error C2440: 'initializing': cannot convert from 'initializer list' to 'std::vector<char *,std::allocator<_Ty>>'
1>        with
1>        [
1>            _Ty=char *
1>        ]
1> note: No constructor could take the source type, or constructor overload resolution was ambiguous

If i changed the element type to 'const char *' like this:

vector<const char*> art = { "a","an","the" };

it can be compiled.Can someone tell me the reason?Thanks a lot.

Answer 1

There are two things going on here. First and the most basic one, is that string literals are const by default in C++. Shadi gave a very good link in his answer .

The second thing is that brace initialization cannot accept narrowing conversions. This is very well explained in the item 7 of Meyers' Effective Modern C++ book, very advisable one.

It's a matter of the type system: when you initialize a container with values within braces, like in { "a","an","the" }; , this braced expression is deduced to have the type std::initializer_lists<const char *> , which then will call the container's constructor that takes an initializer list as a parameter. But, remember that string literals have type const char * in C++, but you declared your vector to hold elements of type char * . This will imply a narrowing conversion const char * -> char * , which brace initialization doesn't allow. Therefore, this constructor is discarded, no other is found, and your compiler complains.

Answer 2

The reason is because string literals are constants and they are being stored in the read-only memory. Why ?

if it suits you, you can alternatively use:

vector<string> art = { "a","an","the" };