[英]items from a list in another list
I have two lists: 我有两个清单:
list1 = ['home', 'school', 'bus', football']
list2 = ['yesterday I went to home', 'I am busy', 385723, 'I feel like
playing football', I was tired last week', 'I go to school by
bus',' there is a bus stop near my home', 'I am hungry']
I wanted to know how can I print any item from list2 that contains any item(at least 1) from list1? 我想知道如何打印list2中包含list1中任何项目(至少1个)的任何项目? for example in our example the following should be printed: 例如,在我们的示例中,应打印以下内容:
'yesterday I went to home','I feel like playing football', 'I go to school
by bus',' there is a bus stop near my home'
I wrote a piece of code but my application breaks when I run it: 我写了一段代码,但是我的应用程序在运行时坏了:
theList = []
i = 0
while i < len(list1):
for element in list2:
if (list1[i]) in element.lower():
theList.append(element)
i += 1
print(errorList)
另一个解决方案:
print([el2 for el2 in list2 if any(el1 in str(el2).split() for el1 in list1)])
Try this out : 试试看:
for string in list2:
if(type(string)==str): #if the element in list2 is a string
if(set(string.split()) & set(list1)): #split the string into words, and check if it has a set intersection with list1
print(string)
OUTPUT : 输出:
yesterday I went to home
I feel like playing football
I go to school by bus
there is a bus stop near my home
try this! 尝试这个! it's from memory but it should work :) 它来自内存,但它应该可以工作:)
# Print Your code here
print('Hello in console window')
list1 = ['home', 'school', 'bus', 'football']
list2 = ['yesterday I went to home', 'I am busy', 385723,
'I feel like playing football', 'I was tired last week'
, 'I go to school by bus'
,' there is a bus stop near my home', 'I am hungry']
theList = []
i = 0
for item in list2:
item1 = str(item).split(" ")
if len(item1) >= 1:
is_in = [x for x in item1 if x.lower() in list1]
else:
is_in = item if item.lower() == list1 else 0
if len(is_in) > 0:
theList.append(item)
for item in theList:
print(item)
Let me know if it errs, 让我知道是否有误,
need to split into words and match. 需要拆分成单词并进行匹配。
list1 = ['home', 'school', 'bus', 'football']
list2 = ['yesterday I went to home', 'I am busy', 385723, 'I feel like playing football',
'I was tired last week', 'I go to school by bus',' there is a bus stop near my home', 'I am hungry']
theList = []
for item2 in list2:
for item1 in list1:
bfound=False
if type(item2) is str:
words = item2.lower().split()
for word in words:
if word==item1:
theList.append(item2)
bfound=True
break
if bfound:
break
print(theList)
output 输出
['yesterday I went to home', 'I feel like playing football', 'I go to school by bus', ' there is a bus stop near my home']
list1 = ['home', 'school', 'bus', 'football']
list2 = ['yesterday I went to home', 'I am busy', '385723',
'I feel like playing football', 'I was tired last week',
'I go to school by bus',' there is a bus stop near my home',
'I am hungry']
ans = []
for s2 in list2:
l2 = s2.split(' ')
for ss in l2:
if ss in list1:
ans.append(s2)
break
print ans
Here is an easily readable multi-line solution, which does not take into account the items of list2
that are not of string
type: 这是一个易于阅读的多行解决方案,该解决方案未考虑list2
的非string
类型的项:
result = []
for sentence in list2:
if isinstance(sentence, str):
for word in list1:
if word in sentence.split():
result.append(sentence)
break
print(result)
Here is also a one-line style solution (I saw it has been already given by @grimek), which converts any items from list2
into string
type: 这也是一个单行样式的解决方案(我已经看到@grimek已经给出了),该解决方案将list2
所有项目转换为string
类型:
result = [sentence for sentence in list2 if any(word in str(sentence).split() for word in list1)]
print(result)
list3 = [s for s in list2 if (type(s)==str) and (set(s.split())&set(list1))]
Try this :-) 尝试这个 :-)
the result for list3 is list3的结果是
['yesterday I went to home', 'I feel like playing football', 'I go to school by bus', ' there is a bus stop near my home'] [“昨天我回家”,“我喜欢踢足球”,“我乘公共汽车去学校”,“我家附近有一个公共汽车站”]
There is a thing if you directly check if 'bus' in string , you can get wrong result because it will check sub_string by_ sub_string, so if you do this on this example: 如果直接检查string中的'bus'会发生什么,您会得到错误的结果,因为它将检查sub_string by_ sub_string,因此如果在此示例中执行此操作:
'bus' in 'I am busy' then it will return True :
So solution is instead of checking sub_string , check word by word : 所以解决方案不是检查sub_string,而是逐字检查:
print([j for i in list1 for j in list2 if isinstance(j,str) if i in j.split()])
output: 输出:
['yesterday I went to home', ' there is a bus stop near my home', 'I go to school by bus', 'I go to school by bus', ' there is a bus stop near my home', 'I feel like playing football']
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