[英]conversing mp4 to wav with the same file name in python
Below are my code and I am trying to convert mp4
file to wav
with some parameter change, like I am changing its frequency and so on. 下面是我的代码,我试图通过一些参数更改将
mp4
文件转换为wav
,例如我正在更改其频率等等。 Now my problem is I have 100 mp4
files in the "inputdir"
folder and I read the file one by 1 and convert it, then I want to save the file with the same name as mp4
file names but with different extension(in my case .wav
). 现在我的问题是我在
"inputdir"
文件夹中有100个mp4
文件,我一一读取了该文件并将其转换,然后我想保存与mp4
文件名相同但扩展名不同的文件(在我的情况下.wav
)。 In my above code, every time I am converting, it's getting saved as out.wav. 在上面的代码中,每次转换时,都将其另存为out.wav。 Can some one suggest me some options please?
有人可以建议我一些选择吗?
I also checked How do I use FFMPEG to create a WAV file with the same name as the input (m4a) file? 我还检查了如何使用FFMPEG创建与输入(m4a)文件同名的WAV文件?
but I don't find any answer. 但我找不到任何答案。
Thanks :) 谢谢 :)
import os
import ffmpy
inputdir = '/home/------my folder path------------'
for filename in os.listdir(inputdir):
actual_filename = filename[:-4]
if(filename.endswith(".mp4")):
os.system("ffmpeg -i {0} -acodec pcm_s16le -ar 16000 out.wav".format(filename))
else:
continue
I want to make it as, 我想做到
os.system("ffmpeg -i {0} -acodec pcm_s16le -ar 16000 actual_filename.wav".format(filename))
I also tried like below. 我也尝试如下。
os.system("ffmpeg -i "$filename" -acodec pcm_s16le -ar 16000 "${actual_filename}".wav".format(filename))
But it does not work. 但这行不通。 I am getting
我正进入(状态
os.system("ffmpeg -i "$filename" -acodec pcm_s16le -ar 16000 "${actual_filename}".wav".format(filename))
^
SyntaxError: invalid syntax
您正在os.system
调用中关闭引号。
os.system('ffmpeg -i {} -acodec pcm_s16le -ar 16000 {}.wav'.format(filename, actual_filename))
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