[英]Calling AWK and Shell Scripting
I'm having a problem with a Shell Script. 我的Shell脚本有问题。
In a nutshell I want to print the "$2" column of the file "$1" in my script "showColumn" 简而言之,我想在脚本“ showColumn”中打印文件“ $ 1”的“ $ 2”列
So, what I've tried: 所以,我试过了:
#!/bin/bash
awk '{print $($2)}' $1
exit 0
Ok, I know that $($2) is totally incorrect, but you can see what I'm trying to do. 好的,我知道$($ 2)完全不正确,但是您可以看到我正在尝试执行的操作。
So what I want when I write "./showColumn file.txt 2" is printing the second column of file.txt but I don't know how to solve that. 因此,当我编写“ ./showColumn file.txt 2”时,我想要打印的是file.txt的第二列,但我不知道该如何解决。
Try: 尝试:
#!/bin/bash
awk -v column="$2" '{print $column}' "$1"
exit 0
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