正则表达式用于查找和替换冒号中的表情符号名称

Question

I'm trying to write a regex (for JavaScript's regex engine) that I can use to do a find and replace in text for emoji names within colons. Like in Slack or Discord when you type :smiley-face: and it replaces it when you submit the chat. I'm targeting text nodes only so I don't need to worry about other html inside the text.

Is it possible to write a regex that could match all of the following rules? (text highlighted with monospace blocks = regex positive matches)

:any-non-whitespace:
:text1: sample2:
:@(1@#$@SD: :s:
:nospace::inbetween: because there are 2 colons in the middle
:nospace: middle :nospace:

I'm starting with something like this but it's incomplete

/:(?!:)\S+:/gim

I'm trying to think of all the special cases that might possibly occur doing this. Maybe I'm overthinking it.

There's a lot of Twitch emotes involved so I can't use emoji unicode characters. The regex will find matches and replace with tags

Answer 1

I suggest using

:[^:\s]*(?:::[^:\s]*)*:

See the regex demo . It is the same pattern as :(?:[^:\\s]|::)*: , but a bit more efficient because the (?:..|...)* part is unrolled .

Details

• : - a colon
• [^:\\s]* - 0+ chars other than : and whitespace
• (?: - start of a quantified non-capturing group:
  • :: - double colon
  • [^:\\s]* - 0+ chars other than : and whitespace
• )* - end of grouping, repeated 0 or more times (due to the * quantifier)
• : - a colon.

Answer 2

My first thought was

:(::|[^:\n])+:

It matches a string, at least one character long, including surrounding colons, that consists of either

• two colons ( :: ), or
• a character that isn't a colon, nor a line feed.

But that's basically what Wiktor had as a (slower) alternative (comments). But I'll leave it here anyway since it's working, as opposed to the other submitted answers ;)

See it here at regex101 .

Answer 3

Do you want something like this regex?

(:(?![\n])[()#$@-\w]+:)

Demo ,,, in which you can additionally insert unallowed characters into the character class of the (?![\\n]) and also additonally insert allowed characters into the character class [()#$@-\\w]

Answer 4

试试这个regx

/(^|\\s)+:([^\\s\\n\\r])+:|^:[^\\s\\n\\r]+/g