如何将结构成员与冒泡排序保持在一起？

Question

I've created a list of names in a .csv file, and I am trying to sort them alphabetically. Right now I've got an array of structs. The struct only has 2 members, the first and last name. I've got my bubble sort to sort based on first name which is what I want, but how can I keep the last name with them? When I print the array back out the last names do not line up with the first name.

void bubbleSort(cred name[], int n) { 

  char temp[25];
  int i,j;

  for(i=1;i<=n;i++)
    for(j=0;j<=n-i;j++)
      if(strcmp(name[j].first,name[j+1].first)>0)
      { 
        strcpy(temp,name[j].first);
        strcpy(name[j].first,name[j+1].first);
        strcpy(name[j+1].first,temp);
      }

   printf("The strings appears after sorting :\n");
   for(i=0;i<=n;i++)
     printf("%s  %s\n",name[i].first,name[i].last);
}

Answer 1

I think your logic appears sound, someone is free to correct me, but you should also swap your last names whenever you swap the first names.

You could also just create a temp of type cred swap the previous element of the array with the next, both of type cred.

Answer 2

Simply replace

    strcpy(temp,name[j].first);
    strcpy(name[j].first,name[j+1].first);
    strcpy(name[j+1].first,temp);

with

    cred t = name[j];
    name[j] = name[j+1];
    name[j+1] = t;

as structs can be assigned to each other there is no need for copying member by member.

Also notice that all your for loops uses <= - like:

for(i=1;i<=n;i++)
         ^^
         here

That seems to be a mistake as n probably represents the number of elements in the array. So your code is indexing out of bounds.

So change all your for loops to use < instead of <=