如何在shell脚本中仅从字符串中剪切“ test2-test”

Question

how to cut word "test2-test" from var="./test3/test2-test-10.23-67.tar.gz"

"test2-test" could be any name, How can I do this?

Answer 1

You can use substring replacement like this:

var="./test3/test2-test-10.23-67.tar.gz"
echo ${var/test2-test/}

Output: ./test3/-10.23-67.tar.gz

Read more about manipulating strings

---

Updating answer to keep only the filename in the path using string replacing and basename :

basename ${var/-[0-9]*.*/}

Output: test2-test

Answer 2

The answer by @Carloluis is nice, but I think the question was not properly framed.

@Samresh wanted to remove the extra part from ./test3/test2-test-10.23-67.tar.gz so that only test2-test remained.

It can be done by following -

basename ./test3/test2-test-10.23-67.tar.gz | sed 's/-[[:digit:]].*//'

'basename' will strip the path out, so only the filename (test2-test) remains. Next, sed can match a regex. So we match the version and file extension and replace it with empty string.

This works for bash 4.2.46.

Answer 3

The answer by @Avi is nice, but a little slow. Pure bash:

#!/bin/bash

var="./test3/test2-test-10.23-67.tar.gz"
var=${var##*/}
var=${var%%-[0-9]*}
echo $var

100 times faster with 10000 iterations

bash   <  sed+basename (no builtin command)
129 ms < 13006 ms