JavaScript对象字符串/引用问题

Question

I have this piece of code:

var selectdata = {
     "tablename": "dbo.vw_bla",
     "where": "ID_Prod like @idprod",
     "whereparameters": [{
         "name": "idprod",
         "value": ' +  $(prodvariable) + ',
         "type": "varchar"
     }],
     "orderby": "ID_Prod ASC"
 };

prodvariable is a variable in which a have stored a number. For example 6 .

This should be passed as 6 .

I have tried several combinations of quotes, escapes, +, etc but I cannot figure out the right way.

Answer 1

If you want to pass the prodvariable as number try like below

var prodvariable = 6
var selectdata = {
     "tablename": "dbo.vw_bla",
     "where": "ID_Prod like @idprod",
     "whereparameters": [{
         "name": "idprod",
         "value": prodvariable,
         "type": "varchar"
     }],
     "orderby": "ID_Prod ASC"
 };

If you want to pass the variable as string try like below

var prodvariable = 6
var selectdata = {
     "tablename": "dbo.vw_bla",
     "where": "ID_Prod like @idprod",
     "whereparameters": [{
         "name": "idprod",
         "value": `${prodvariable}`, 
         "type": "varchar"
     }],
     "orderby": "ID_Prod ASC"
 };

You could do one of the following method to pass prodvariable to json object.

"value": prodvariable // this will be passed as number if prodvariable is number

"value": ${prodvariable} ,

OR

"value": '"'+ prodvariable + '"',

Answer 2

You do not need any quotes for prodvariable . Use that variable directly in the value:

 var prodvariable = '6'; var selectdata = {"tablename":"dbo.vw_bla", "where":"ID_Prod like @idprod", "whereparameters": [ {"name": "idprod", "value": prodvariable , "type":"varchar"}], "orderby":"ID_Prod ASC"}; console.log(selectdata); 

Answer 3

If I understand correctly, you want to use the value of the prodvariable variable but surrounded with double quotes? You can do so using ES2015 string template literals:

{ "value":  `"${prodvariable}"` }

Then value will be "6" in your case.

You can achieve the same result with simple string concatenation as well:

{ "value":  '"' + prodvariable + '"' }