[英]Return sum of unique word occurrences from a text file using python
I am trying to update an older script of mine for a class. 我正在尝试为课程更新我的旧脚本。 Typically this script will just record a '1' if any of the items from a list appear in that line.
通常,如果列表中的任何项目出现在该行中,则此脚本只会记录“ 1”。 However, now I want it to count and sum the number of times any of those unique words appear in that line.
但是,现在我希望它计算和总结那些唯一单词在该行中出现的次数。 For example, using this list:
例如,使用以下列表:
ess = ['jim','bob','sally','tom']
.
.
.
elif 'SCHOOL' in line:
csvfile.write( str(line.count(',') + 1)+ ',')
flag = 0
for staff in ess:
if staff in line:
csvfile.write('1')
flag = 1
break
if flag == 1:
csvfile.write('\n')
else:
csvfile.write('0\n')
Instead of simply recording a "1" if any of the names appear. 如果出现任何名称,而不是简单地记录“ 1”。 I would like it return a sum of how many names appear in that line.
我希望它返回该行中出现多少个名称的总和。 For example, if both jim and sally appear in that line, return a "2"
例如,如果吉姆和莎莉都出现在该行中,则返回“ 2”
You can simply run multiple count on the string/sentence. 您可以简单地对字符串/句子运行多个计数。
or you can split
the sentence by " " (space) delimiter and go over that returned list and check each word is equal to one of your desired words: 或者您也可以
split
为“”(空格)分隔这句话,走了过来说返回的列表,并检查每个字等于你想要的话之一:
I would of do something like that: 我会做这样的事情:
sum = 0
for line in lines:
split_list = line.split(" ")
for word in ess:
if word in split_list :
sum+=1
or alternative: sum = 0 for line in lines: for word in ess: sum += line.count(word) 或替代:sum = 0表示行中的行:for ess中的单词:sum + = line.count(word)
There are two ways to attempt this: 有两种方法可以尝试此操作:
1) You do not care how many times a name appears in the sentence as long as the name appears at least once: 1)您不在乎一个名称出现在句子中的次数,只要该名称至少出现一次即可:
def names_in_sentence(sentence_str):
return sum([1 for name in lis_names if name in sentence_str])
This is a fairly pythonic way of doing it. 这是一种相当蟒蛇的方法。 I am using list comprehension to create a list of 1's for each name that is there in the input sentence.
我正在使用列表推导为输入句子中存在的每个名称创建一个1的列表。
2) You do care about how many times a name appears in the sentence. 2)您确实关心一个句子中一个名字出现了多少次。 ie if the sentence was "This is a bob, he's quite the bob', you would return 2:
例如,如果句子是“这是一个鲍勃,他是个鲍勃”,您将返回2:
def names_in_sentence(sentence_str):
return sum([sentence.count(name) for name in lis_names])
In this case, I use list comprehension to count the number of times each name appears in the sentence, and sum the list. 在这种情况下,我使用列表推导来计算每个名称在句子中出现的次数,并对列表求和。
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