Access SQL-根据多列中的条件返回唯一行

Question

I have two tables of zipcodes containing drivetime data. The first (called "DTM") contains 4 columns. The first two columns are From and To zipcodes, followed by drivetime and driving distance between them. This table contains every combination of zipcodes twice, with From and To zips reversed. it looks something like this:

FROM_ZIP  TO_Zip  Drivetime(min)  Distance(mtr)
1011      1011    0                0
1011      1012    3                650
1011      1013    4                850
1011      1014    4                900
1012      1011    3                650
1012      1012    0                0 
1012      1013    2                500
...

This table contains roughly 16.5 million records.
The second table (called "STOREZIPS") contains a list of zipcodes belonging to stores.

My goal here is to match every zipcode in the country to the zipcode of the store that is closest by, and show the drivetime and driving distance. So what i'm trying to do is extract from the first table the rows in which the TO_Zip matches one of the zipcodes in the second table, and have the lowest Drivetime(min) .

There are however also instances where two Zip's have the same Drivetime(min) to another Zip. If this occurs the row with the lowest Distance(mtr) should be selected.

I've been trying to solve this for a while now, but just can't seem to get it in such a way that only the From_Zip that is closest by gets selected.

Any help or suggestion is appreciated.

Answer 1

I think that you will need to use CTE in that case. You can read more here: https://technet.microsoft.com/en-us/library/ms190766(v=sql.105).aspx

If I understood you well I think that sample sql may look like this:

with cte as 
(
    select min(c.Drivetime) as minimum, c.zipT, 
    c.Distance, rank() over (partition by c.TO_Zip order by   c.Distance) as place      
    from DTM c
    inner join STOREZIPS s on c.TO_Zip = s.TO_Zip
    where c.Drivetime > 0
    group by c.TO_Zip, c.Distance   
 ) select * from cte where place = 1