[英]groovy extract value from string
I got a string from a server response: 我从服务器响应中得到了一个字符串:
responseString:"{"session":"vvSbMInXHRJuZQ==","age":7200,"prid":"901Vjmx9qenYKw","userid":"user_1"}"
then I do: 然后我做:
responseString[1..-2].tokenize(',')
got: 得到:
[""session":"vvSbMInXHRJuZQ=="", ""age":7200", ""prid":"901Vjmx9qenYKw"", ""userid":"user_1""]
get(3) got: get(3)得到了:
""userid":"user_1""
what I need is the user_1, is there anyway I can actually get it? 我需要的是user_1,反正我真的可以得到它吗? I have been stuck here, other json methods get similar result, how to remove the outside ""? 我被困在这里,其他json方法也得到类似的结果,如何删除外面的“”?
Thanks. 谢谢。
If you pull out the proper JSON from responseStr
, then you can use JsonSlurper
, as shown below: 如果从responseStr
提取正确的JSON,则可以使用JsonSlurper
,如下所示:
def s = 'responseString:"{"session":"vvSbMInXHRJuZQ==","age":7200,"prid":"901Vjmx9qenYKw","userid":"user_1"}"'
def matcher = (s =~ /responseString:"(.*)"/)
assert matcher.matches()
def responseStr = matcher[0][1]
import groovy.json.JsonSlurper
def jsonSlurper = new JsonSlurper()
def json = jsonSlurper.parseText(responseStr)
assert "user_1" == json.userid
This code can help you get you to the userid. 此代码可以帮助您获得用户ID。
def str= 'responseString:"{:"session":"vvSbMInXHRJuZQ==","age":7200,"prid":"901Vjmx9qenYKw","userid":"user_1","hdkshfsd":"sdfsdfsdf"}'
def match = (str=~ /"userid":"(.*?)"/)
log.info match[0][1]
this pattern can help you getting any of the values you want from the string. 此模式可以帮助您从字符串中获取所需的任何值。 Try replacing userid with age, you will get that 尝试将用户ID替换为年龄,您将获得
def match = (str=~ /"age":"(.*?)"/)
@Michael code is also correct. @Michael代码也是正确的。 Its just that you have clarified that you want the user Name to be specific 只是您已经澄清了您想要特定的用户名
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