[英]Run two promises asynchronously, but prioritize the result of the first promise
I'm developing an JS simple project that requires taking the json result (via fetch() or XHR) from 2 services. 我正在开发一个JS简单项目,需要从2个服务中获取json结果(通过fetch()或XHR)。 The first is the main service, and the second acts as a fallback.
第一个是主要服务,第二个充当后备。 Each of them can be slower than the other (hint: it's a dictionary app, and 2 service is Wiktionary and Google Translate).
它们每个都可能比另一个慢(提示:这是一个字典应用程序,其中2个服务是Wiktionary和Google Translate)。
To get a little faster speed, I'm thinking it would be better if I get both of the results asynchronously (in parallel). 为了获得更快的速度,我认为如果异步(并行)获得两个结果会更好。 It still prefer the result of service #1 whether it's fast or slow, and ignore (or abort) the service #2's task.
无论速度是快还是慢,它仍然更喜欢服务1的结果,而忽略(或中止)服务2的任务。
But if it failed to get the result of service #1, then the result of service #2 will be used as alternative. 但是,如果未能获得服务1的结果,则将服务2的结果用作替代。 And because both services are run in parallel (from one point of time), service #2's result can be returned as fast as possible.
并且由于两个服务都是并行运行的(从一个时间点开始),因此可以尽快返回服务2的结果。
Please see my pseudo example here. 请在这里查看我的伪示例。
const setTimeOutP = (time, label, re = false) => { return new Promise((resolve, reject) => { setTimeout(function(){ if(re == false) resolve(label); else reject(label); },time); }); }; promiseOneMustBeReturnedUnlessReject([setTimeOutP(1000, "promise 1"), setTimeOutP(3000, "promise 2")]); // Promise 1 (in 1s), similar to Promise.race promiseOneMustBeReturnedUnlessReject([setTimeOutP(3000, "promise 1"), setTimeOutP(1000, "promise 2")]); // Promise 1 (in 3s) promiseOneMustBeReturnedUnlessReject([setTimeOutP(1000, "promise 1", true), setTimeOutP(3000, "promise 2")]); // Promise 2 (in 3s), NOT 4s promiseOneMustBeReturnedUnlessReject([setTimeOutP(4000, "promise 1", true), setTimeOutP(2000, "promise 2")]); // Promise 2 (in 4s), NOT 6s promiseOneMustBeReturnedUnlessReject([setTimeOutP(4000, "promise 1", true), setTimeOutP(2000, "promise 2", true)]); // Reject in 4s
I have a dirty solution right now that I think it would work like I described: 我现在有一个肮脏的解决方案,我认为它可以像我描述的那样工作:
const printResult = async (key) => {
let dataObj = {
wiktionary: {
status: "pending"
},
googleTranslate: {
output: "",
status: "pending"
}
};
wiktionary(key).then(result => {
document.getElementById("result").innerHTML = result;
dataObj.wiktionary.status = "printed";
}).catch((error) => {
if (dataObj.googleTranslate.status == "ready") {
document.getElementById("result").innerHTML = dataObj.googleTranslate.output;
} else if (dataObj.googleTranslate.status == "error") {
throw new Error(error);
} else {
dataObj.wiktionary.status = "error";
}
});
googleTranslate(key).then(result => {
if (dataObj.wiktionary.status == "error") {
document.getElementById("result").innerHTML = result;
dataObj.googleTranslate.status = "printed";
} else {
dataObj.googleTranslate.output = result;
dataObj.googleTranslate.status = "ready";
}
}).catch((error) => {
if (dataObj.wiktionary.status == "error") {
throw new Error(error);
} else {
dataObj.googleTranslate.status = "error";
}
});
};
But is there any more elegant way to handle this situation? 但是,有没有更优雅的方式来处理这种情况呢?
You can start both promises, then return the fallback in case of error: 您可以启动两个promise,然后在发生错误的情况下返回后备:
const translate = key => {
const fallback = googleTranslate(key);
return wiktionary(key)
.catch(() => fallback);
};
used as follows: 用法如下:
const printResult = async key => {
const result = await translate(key);
document.getElementById("result").innerHTML = result;
};
If you have a cancellation mechanism, use it in a .then()
before the .catch()
. 如果你有一个取消机制,使用它的
.then()
的前.catch()
You don't have to put .then
handlers on promises immediately - you can wait until they're necessary. 您不必立即将
.then
处理程序置于promise中-您可以等到必要时再使用它们。 If the promise has already been resolved by the time you put the new .then
on it, the new .then
will run immediately. 如果承诺在您将新
.then
放在其上时已得到解决,则新.then
将立即运行。
const printResult = (key) => {
const googleProm = googleTranslate(key);
const resultElm = document.getElementById("result");
wiktionary(key)
.then(mainResult => resultElm.textContent = mainResult)
.catch((mainError) => {
googleProm.then(googleResult => resultElm.textContent = googleResult)
.catch(googleError => throw new Error(error));
});
};
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