PHP MySQL：浏览每一行，并计算有多少列满足条件

Question

I've got a table similar to:

|       | column1 | column2 | column3 | column4 |
|-------|---------|---------|---------|---------|
| user1 | 100     | 49      | 3       | 1,980   |
| user2 | 7       | 5       | 51      | 500     |
| user3 | 1       | 65      | 44      | 37      |

I want to go through all the rows, and for each of those rows, I want to select the count() relating to how many columns meet a criteria ( value < 100 , for example)

So the result of each row calculating value < 100 would be:

user1: 2
user2: 3
user3: 4

Does anyone have an idea how to go about this? I can't seem to find any answers for a question this specific.

Thanks!

Answer 1

I totally forgot about just doing a simple, hardcoded query.

This solution works for me:

SELECT user,              (column1 < 100) +
                          (column2 < 100) +
                          (column3 < 100) +
                          (column4 < 100)
AS total FROM table;

Thanks to the commenters - I had overlooked this simple solution.