在Java中等效于curl命令

Question

我想要一些帮助在Java中编写等效于下面的curl命令的内容。

curl -X POST --header 'Content-Type: application/json' --header 'Accept: application/json' --header  'cookie: [APP COOKIES];' -d 'sampleFile.json' 'https://url.com'

Answer 1

您尝试使用RESTful Web服务，因此应使用jax-rs或spring REST之类的库，这是使用RESTful Web服务的示例，您可以找到许多具有更多详细信息的示例。

Answer 2

I think that the answer you are looking for is which library provides Java to create HTTP requests. What is the best Java library to use for HTTP POST, GET etc.? This question provides you with all the answers that you need

Answer 3

With HttpClient of apache you can do it:

...
import org.apache.http.client.methods.HttpPost;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity
import org.apache.http.Consts;
import org.apache.http.client.methods.CloseableHttpResponse;
import org.apache.http.HttpEntity;
....

public String sendPost(String url, Map<String, String> postParams, 
        Map<String, String> header, String cookies) {

    HttpPost httpPost = new HttpPost(url);
    List<NameValuePair> formParams = new ArrayList<NameValuePair>();
    HttpClientBuilder clientBuilder = HttpClients.createDefault();
    CloseableHttpClient httpclient = clientBuilder.build();

    if (header != null) {
        Iterator<Entry<String, String>> itCabecera = header.entrySet().iterator();
        while (itCabecera.hasNext()) {
            Entry<String, String> entry = itCabecera.next();

            httpPost.addHeader(entry.getKey(), entry.getValue());
        }
    }

    httpPost.setHeader("Cookie", cookies);

    if (postParams != null) {
        Iterator<Entry<String, String>> itParms = postParams.entrySet().iterator();
        while (itParms.hasNext()) {
            Entry<String, String> entry = itParms.next();

            formParams.add(new BasicNameValuePair(entry.getKey(), entry.getValue()));
        }
    }

    UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(formParams, Consts.UTF_8);
    httpPost.setEntity(formEntity);

    CloseableHttpResponse httpResponse = httpclient.execute(httpPost);

    HttpEntity entity = httpResponse.getEntity();
    if (entity != null) {
        pageContent = EntityUtils.toString(entity);
    }

    return pageContent;
}

I hope this help you.

EDIT:

I add the way to send a file. I put in a code separate to not mix code (it is an approximation, based on this examples ):

File file = new File("path/to/file");
String message = "This is a multipart post";
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);

if (postParams != null) {
    Iterator<Entry<String, String>> itParms = postParams.entrySet().iterator();
    while (itParms.hasNext()) {
        Entry<String, String> entry = itParms.next();

        builder.addTextBody(entry.getKey(), entry.getValue(), ContentType.DEFAULT_BINARY);
    }
}

builder.addTextBody("text", message, ContentType.DEFAULT_BINARY);

HttpEntity entity = builder.build();
httpPost.setEntity(entity);