[英]javascript iterative logical XOR for array of objects?
I have a function that loops over 2 arrays of Feature objects and checks if each Feature's active
property has changed. 我有一个循环2个Feature对象数组并检查每个Feature的active
属性是否已更改的函数。 So far I have this: 到目前为止,我有这个:
const changes = [];
let index = 0;
features.forEach((feature) => {
if (feature.active && !originalFeatures[index].active) {
return changes.push({ name: feature.name, change: 'Activated' });
}
if (!feature.active && originalFeatures[index].active) {
return changes.push({ name: feature.name, change: 'Deactivated' });
}
index += 1;
});
A) The code doesn't work, there's a logic error I can't seem to bust. A)代码不起作用,有一个逻辑错误我似乎无法解决。 After changing the active state of a single feature, the function outputs changes
as an array of half the features being 'Activated'. 更改单个功能部件的激活状态后,该功能将输出changes
为“已激活”功能部件的一半的阵列。 Note I have asserted the two input arrays as containing the correct objects and property values before the function is run. 注意在运行函数之前,我断言两个输入数组包含正确的对象和属性值。
B) is there a faster built in function that could simplify the process from these if statements? B)是否有更快的内置函数可以简化这些if语句的过程?
Am relatively new to javascript so any ideas would be greatly appreciated, thanks 对javascript来说相对较新,因此任何想法都会受到赞赏,谢谢
is there a faster way that could simplify the process from these if statements? 有没有更快的方法可以简化这些if语句的过程?
Sure, just write a single statement 当然,只写一个语句
if (feature.active != originalFeatures[index].active) {
return changes.push({
name: feature.name,
change: feature.active ? 'Activated' : 'Deactivated'
});
}
You could also use the actual XOR operator ^
but since we are working with booleans here I prefer !=
. 您也可以使用实际的XOR运算符^
但是由于我们在这里使用布尔值,因此我更喜欢!=
。
I prefer the use of Array.prototype.map
, Array.prototype.filter
and Array.prototype.reduce
over Array.prototype.forEach
. 我更喜欢使用Array.prototype.map
, Array.prototype.filter
和Array.prototype.reduce
超过Array.prototype.forEach
。
Untested: 未经测试:
const changes = features.reduce((filtered, feature, index) => {
if (feature.active ^ originalFeatures[index].active) {
filtered.push({ name: feature.name, change: (feature.active) ? 'Activated' : 'Deactivated' }})
}
return filtered;
}, []);
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