[英]How to access data of [object object] AngularJS
I am new to AngularJS. 我是AngularJS的新手。 I am sending a JsonObject to another state.
我正在将JsonObject发送到另一个状态。
Ex: 例如:
viewScope.edit=function(d) {
var viewData = {
'name' : d.name,
};
$state.go('edit', {'viewD': viewData}, {reload: true});
};
My State is- 我的状态是-
viewApp.config(function($stateProvider){
$stateProvider
.state('edit', {
name: '#/edit',
url: '/register/{viewD}',
templateUrl: function(){
return path+'/register.jsp';
},
controller:'registerCtrl',
resolve : {
loadPlugin: function($ocLazyLoad) {
return $ocLazyLoad.load([{
name : 'registerApp',
files: [path+'/resources/js/register.js'],
}])
}
}
})
});
In register Controller getting data- 在寄存器控制器中获取数据
regApp.controller('registerCtrl',function($stateParams){
if($stateParams != undefined){
console.log($stateParams.viewD);
}
});
On console output is- [object object] 在控制台上的输出是-[object object]
How can i access the name key from this [object object]. 我如何从此[对象对象]访问名称键。
console.log($StateParams.viewD.name); console.log($ StateParams.viewD.name); // Not Working
//不起作用
JSON.parse, JSON.stringify not working. JSON.parse,JSON.stringify无法正常工作。
Change your config method as following, 如下更改您的配置方法,
viewApp.config(function($stateProvider){
$stateProvider
.state('edit', {
name: '#/edit',
url: '/register',
params: {
viewD: null
}
templateUrl: function(){
return path+'/register.jsp';
},
controller:'registerCtrl',
resolve : {
loadPlugin: function($ocLazyLoad) {
return $ocLazyLoad.load([{
name : 'registerApp',
files: [path+'/resources/js/register.js'],
}])
}
}
})
});
And then you can access your object from $state
like this in the controller, $state.params.viewD
or from $stateParams
like this $stateParams.viewD
然后,您可以从
$state
这样在控制器$state.params.viewD
访问对象,或者从$stateParams
这样访问$stateParams.viewD
Now try console.log($state.params.viewD.name)
现在尝试
console.log($state.params.viewD.name)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.