[英]Python Print parameter end
How to remove the last "add -->" from the output when using end, i am not using sep here, bcoz sep will not have any effect here , as the print statement prints just 1 item at a time here and ends with incr of i 使用end时如何从输出中删除最后一个“ add->”,我在这里不使用sep,bcoz sep在这里不会有任何效果,因为print语句一次只打印1个项目,并以incr结尾我的
def fibonaci_num(n):
if n <= 1:
return n
else:
return fibonaci_num(n-1) + fibonaci_num(n-2)
N = 10
for i in range(N):
print(fibonaci_num(i), end=' add -> ')
my output 我的输出
0 add -> 1 add -> 1 add -> 2 add -> 3 add -> 5 add -> 8 add -> 13 add -> 21 add -> 34 add ->
you can use an if statement to check if its the last number: 您可以使用if语句检查其最后一个数字:
def fibonaci_num(n):
if n <= 1:
return n
else:
return fibonaci_num(n-1) + fibonaci_num(n-2)
N = 10
for i in range(N):
print(fibonaci_num(i), end='')
if i != N-1:
print(' add -> ', end='')
不可避免的pythonic一线:
print(*map(fibonaci_num, range(N)), sep=' add -> ')
Here I've simplified answer using ternary operator. 在这里,我使用三元运算符简化了答案。 May it will be helpful and better.
希望它会有所帮助并且变得更好。
def fib(n):
a, b = 0, 1
while a < n:
endstatement = '-' if (b < n) else ''
print(a, end=endstatement)
a, b = b, a+b
print()
# Now call the function:
fib(1000)
Result :
0-1-1-2-3-5-8-13-21-34-55-89-144-233-377-610-987
结果 :
0-1-1-2-3-5-8-13-21-34-55-89-144-233-377-610-987
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