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PHP数组-计算唯一ID

[英]PHP array - count unique IDs

I have a PHP array that looks like this 我有一个看起来像这样的PHP数组

Array
(
    [0] => Array
        (
            [events] => Array
                (
                    [0] => Array
                        (
                            [label] => apple
                            [id] => 3
                        )
                        [1] => Array
                        (
                            [label] => onion
                            [id] => 3
                        )
                        [2] => Array
                        (
                            [label] => pear
                            [id] => 2
                        )
                        [3] => Array
                        (
                            [label] => orange
                            [id] => 1
                        )
                        [4] => Array
                        (
                            [label] => grape
                            [id] => 41
                        )
                )
        )
)

I am trying to get a total count of unique IDs, so in the example above I would want to get a count of 4 我正在尝试获取唯一ID的总数,因此在上面的示例中,我希望获得4个

Do I need to loop through the array or is there a function that can do it more efficiently? 我是否需要遍历数组,或者是否有一个函数可以更有效地执行此操作? Currently it is a small data set but it could grow fairly large. 目前,这是一个很小的数据集,但可能会变得相当大。

您可以使用array_column获取所有ID,并使用array_unique删除重复项,然后对其进行计数。

count(array_unique(array_column($array[0]['events'][0], 'id')))

One way or another you'll have to loop through it. 一种或另一种方式,您将不得不遍历它。 I think most efficiently would be 我认为最有效的方法是

function getUnique($arr){
 $val = array();
  foreach($arr[0]["events"] as $v){
   $val[$v["id"]] = true;
  }
 return count($val);
}

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